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joja [24]
3 years ago
9

The price of one share of stock A changed by a total of -$4.32 over the past 3 days. The price of one share of stock B changed b

y a total of -$5.80 over the past 4 days. The price of one share of stock C changed by a total of -$2.86 over the past 2 days. Match the stocks to their daily average change in price for one share.
Mathematics
1 answer:
Nataly [62]3 years ago
4 0

Answer:

Stock A daily average change in price for one share = -$2.16

Stock B daily average change in price for one share = -$1.45

Stock C daily average change in price for one share = -$1.43

Step-by-step explanation:

Since we desire to find the price of each stock per day or its daily average change in price for one share, we divide the price change of one share of stock by the total number of days it took to change.

So for stock A, daily average change = price change/number of days

price change = -$4.32, number of days = 2

daily average change  =  -$4.32/2 =  -$2.16

for stock B, daily average change = price change/number of days

price change = -$5.80, number of days = 4

daily average change  =  -$5.80/4 =  -$1.45

for stock C, daily average change = price change/number of days

price change = -$2.86, number of days = 2

daily average change  =  -$2.86/2 =  -$1.43

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Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
3 years ago
What is x?<br> -5 (x - 1) = 40
masha68 [24]

Answer:

x=  -7

Step-by-step explanation:

have a good day

6 0
3 years ago
Read 2 more answers
I need help please ..
koban [17]

A is 18

B is 162

C is 18

D is 162

4 0
3 years ago
Someone Please Help.
ahrayia [7]

Hi there!

\large\boxed{f(-6) = 5}

The value of f(-6) is the y-value at the x-coordinate x = -6.

Looking at the graph, we can see that at x = -6, y = 5.

Therefore, f(-6) = 5.

4 0
3 years ago
How do the 5s in 50.8 and 18.35 compare?
telo118 [61]

The value of the 5 in 50.8 is 1,000 times the value of the 5 in 18.35 ⇒ 1st answer

Step-by-step explanation:

Let us revise some important notes in a number:

  • Every digit in a number has a place value
  • Place value is the value represented by a digit in a number
  • Ex: the place value of 2 in the number 2,345 is 1,000 because 2 is in the thousands place, the place value of 9 in 12.29 is 0.01 because 9 is in the hundredths place

∵ The number is 50.8

∵ 5 is in the tens place

∴ The place value of 5 is 10

∵ The number is 18.35

∵ 5 is in the hundredths place

∴ The place value of 5 is 0.01

Let us compare between the places value of 5 in the two numbers

Let x the number which multiplying by the hundredth digit to give the ten digit

∵ 10 = x × 0.01

∴ 10 = 0.01 x

- Divide both sides by 0.01

∴ 1,000 = x

∵ 5 × 10 = 0.05 × 1000

∴ 50 = 50

∴ The value of 5 in 50.8 = 1,000 × the value of 5 in 18.35

The value of the 5 in 50.8 is 1,000 times the value of the 5 in 18.35

Learn more:

You can learn more about the place value in brainly.com/question/13174282

#LearnwithBrainly

6 0
3 years ago
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