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Artist 52 [7]
3 years ago
7

Expand the following using either the Binomial Theorem or Pascal’s Triangle. You must show your work for credit.. . (2x + 4)^3

Mathematics
2 answers:
Alik [6]3 years ago
7 0
A Pascal triangle is the triangular way of expanding a binomial. So the best way in expanding that function is thru Binomial Theorem and the expanded for of it is 8x^3+48x^2+98x+64
hjlf3 years ago
3 0

Before even trying to put this into the binomial form, we must figure out the coefficients. If we go by the Pascal's Triangles way we should end up with:

        1

    1      1

 1     2     1

1    3     3    1

Going by the last level (which is the third level) we get 3C0:1, 3C1:3, 3C2:3, 3C3:1.

Now with the equation: (a+b)^3 = 3C0a^3 + 3C1a^2 b + 3C2a b^2 + 3C3b^3 we just plug in all the values and simplify

(2x+4)^3 = 2x^3 + 3(2x)^2 (4) + 3(2x) (4)^2 + (4)^3

(2x+4)^3 = 8x^3 + (3)(4x^2)(4) + (3)(2x)(16) + 64

Then we finally end with: (2x+4)^3 = 8x^3 48x^2 + 96x +64



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in a certain population, 11% of people are left-handed. Suppose that you plan to randomly select 100 people and ask each person
Assoli18 [71]

Answer:

c. A and C

Step-by-step explanation:

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=100, p=0.11)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We need to check the conditions in order to use the normal approximation.

np=100*0.11=11 > 10 \geq 10

n(1-p)=100*(1-0.11)=99 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=100*0.11=11

\sigma=\sqrt{np(1-p)}=\sqrt{100*0.11(1-0.11)}=3.129

Part A

We want this probability:

P(X \geq 12) = 1-P(X

The z score is defined as

Z=\frac{x-\mu}{\sigma}.

P(X \geq 12) = 1-P(X

Part B

P(X>12) = 1-P(X\leq 12) = 1-P(Z< \frac{12-11}{3.129})=1-0.625=0.375[/tex]

Part C

P(10\leq X \leq 14) = P(X

The z score is defined as

Z=\frac{x-\mu}{\sigma}.

P(10 \leq X \leq 14) =P(Z< \frac{14-11}{3.129}) -P(Z< \frac{10-11}{3.129})=P(Z

So then the best option is : c. A and C

8 0
4 years ago
Classify: -5x3-11x2+x
Usimov [2.4K]
-15-22+x

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I think that's the answer (at least that's what I got) hope this helps★
5 0
3 years ago
5. Which of the following equations is in standard form?
goldfiish [28.3K]

Answer:

the answer is B

Step-by-step explanation:

3 0
3 years ago
Solve m-3/7 = -5 show your work please :)
Bingel [31]
Add 3/7 to both sides

m=-5+3/7
m=-35/7+3/7
m=-32/7
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