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Zolol [24]
3 years ago
5

5. Circle A has a radius of 9 units . Point R lies 5 units away from A. A chord drawn through R is partitioned by the diameter o

f A passing through R into two segments, one of which has a length of 7 units. Is the length of the other segment longer or shorter than 7 units ? Justify your answer.

Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

The length of the other segment is longer than 7 units

Step-by-step explanation:

we know that

The<em> i</em><u><em>ntersecting chords theorem</em></u> states that the products of the lengths of the line segments on each chord are equal

see the attached figure to better understand the problem

Remember that the diameter of the circle is two times the radius

D=2(9)=18\ units

Let

x ----> the length of the other segment

so

(9+5)(4)=(7)(x)

56=7x\\x=8\ units

therefore

The length of the other segment is longer than 7 units

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Hi! what’s the question? i believe you only put two answers
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Add or subtract. use the least common multiple as the denominator what is 5/8-5/25
Vinvika [58]

Answer:

17/40

Step-by-step explanation:

First let's find the least common denominator. The denominators are 8 and 25 so we need to find the least common multiple of 8 and 25.

8=2*2*2

25=5*5

Since they share no common factors the least common multiple of 8 and 25 is 8*25 which is 200.

Now we convert the fractions:

5/8*25/25=125/200

5/25*8/8=40/200

Then we subtract:

125/200-40/200=85/200

Now we simplify it:

17/40

8 0
2 years ago
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5 0
3 years ago
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The film starts at 6.45 pm The film last 102 minutes what time dose the film finish
Brrunno [24]

Answer:

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8 0
2 years ago
Which simplifications of the powers of i are correct? There may be more than one correct answer.
fredd [130]

\bf i^2=-1\qquad\qquad i^3=-i\qquad \qquad i^4=1 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ i^{22}\implies i^{(4\cdot 5)+2}\implies i^{4\cdot 5}i^2\implies (i^4)^5 i^2\implies 1^5(-1)\implies -1~\dotfill \bigotimes \\\\\\ i^{11}\implies i^{(2\cdot 5)+1}\implies (i^2)^5 i\implies (-1)^5(i)\implies -i~\dotfill \checkmark

\bf i^{21}\implies i^{(4\cdot 5)+1}\implies (i^4)^5 i\implies 1^5(i)\implies i~\dotfill \checkmark \\\\\\ i^{12}\implies i^{3\cdot 4}\implies i^3 i^4\implies (-i)(1)\implies -i\dotfill \bigotimes \\\\\\ i^{20}\implies i^{4\cdot 5}\implies (i^4)^5\implies 1~\dotfill \checkmark \\\\\\ i^{26}\implies i^{(4\cdot 6)+2}\implies (i^4)^6 i^2\implies 1^6(-1)\implies -1\dotfill \checkmark \\\\\\ i^{27}\implies i^{(4\cdot 6)+3}\implies (i^4)^6 i^3 \implies 1^6(-i)\implies -i\dotfill \bigotimes

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3 years ago
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