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Zolol [24]
3 years ago
5

5. Circle A has a radius of 9 units . Point R lies 5 units away from A. A chord drawn through R is partitioned by the diameter o

f A passing through R into two segments, one of which has a length of 7 units. Is the length of the other segment longer or shorter than 7 units ? Justify your answer.

Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

The length of the other segment is longer than 7 units

Step-by-step explanation:

we know that

The<em> i</em><u><em>ntersecting chords theorem</em></u> states that the products of the lengths of the line segments on each chord are equal

see the attached figure to better understand the problem

Remember that the diameter of the circle is two times the radius

D=2(9)=18\ units

Let

x ----> the length of the other segment

so

(9+5)(4)=(7)(x)

56=7x\\x=8\ units

therefore

The length of the other segment is longer than 7 units

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M∠A = 75 + 5x
Firlakuza [10]

Answer:

See below

Step-by-step explanation:

For a parallelogram m < A = m < C so:-

75 + 5x = 87 + 3x

2x = 12

x = 6  

and m< A = 75 + 30 = 105

and m < C = 87 + 18 = 105

Now if the other 2 angles are  = 75 degrees( that is the same side angles add up to 180 degrees) we have proved that it is a parallelogram.

m < B = m < D

111 - 6x = 39 + 6x

-12x = -72

x = 6

m < B = 111 - 36 = 75 and m < D = 39 + 36 = 75

So this has been proved.

6 0
3 years ago
Find the missing length. The triangles are similar.
hodyreva [135]

Answer:

182

Step-by-step explanation:

First, we can say that ∠ACB and ∠BCF are opposite angles because they are not next to each other and are formed by intersecting lines. Therefore, ∠ACB = ∠BCF

Next, angles correspond with the side opposite of it. This means that, for example, ∠ACB corresponds with line AB and ∠BCF corresponds with line BF. Because ∠ACB and ∠BCF are equal and the triangles are similar, we can say that their corresponding sides have a ratio with each other. Similarly, ∠CAB corresponds to CB, ∠ABC corresponds to AC, ∠CWV corresponds to CV, and ∠CVW corresponds to CB.

Because the triangle CVW is isosceles, we can say that the angles whose corresponding sides are equal are equal as well, so ∠CAB = ∠ABC and ∠CVW = ∠CVW. Next, because ∠ACB and ∠BCF are equal and correspond to each other, and the other two angles in each triangle are equal to each other, we can say that the other two angles must be equal. Another way of putting this is like this:

Say that x = ∠CAB. Then,

∠CAB + ∠ABC + ∠ACB = 180

x + x + ∠ACB = 180

2x + ∠ACB = 180

subtract ∠ACB from both sides

180 - ∠ACB = 2x

Similarly, if y = ∠CWV,

180 - ∠WCV = 2y. Therefore, 2y=2x and y=x, so ∠CAB = ∠ABC = ∠CWV = ∠CVW.

Given this, we can say that sides CV and CW correspond with BC and AC. This means that the ratio between, for example, CV and BC is equal to the ratio between CW and AC. Therefore,

CV/BC = CW/AC

84/182 = 84/?

Filling in the blank, 84/182 is equal to 84/182, so ? = 182

8 0
3 years ago
In circle E shown, chords AB and CD are parallel. (a) What does this information tell you about 1  and 2  ? Why? (b) Given you
sp2606 [1]

Answer:

6835

Step-by-step explanation:

58gfbhfm

4 0
3 years ago
Joshua has math and reading homework tonight. Joshua can solve each math problem in 2.5 minutes and he can read each page in 3 m
liraira [26]

Answer:

Joshua solved 7 math problems and tread 14 pages.

Step-by-step explanation:

Let x be the number of math problems Joshua solved. The number of pages Joshua read is twice the number of math problems he solved, then 2x is the number of pages Joshua read.

Joshua can solve each math problem in 2.5 minutes, then x math problems he solves in 2.5x minutes.

Joshua can read each page in 3 minutes, then 2x pages he reads in 3\cdot 2x=6x minutes.

It took him 59.5 minutes to complete all of his homework, so

2.5x+6x=59.5

Solve this equation:

2.5x+6x=59.5\\ \\8.5x=59.5\\ \\85x=595\\ \\x=7\\ \\2x=14

Joshua solved 7 math problems and tread 14 pages.

5 0
3 years ago
Read 2 more answers
Consider the expression −2 + 5a + b + 2a − 5b.
liraira [26]
Like terms will have exactly the same variables

so 5a and 2a are like terms

examples :
3b and 4b are like terms
3b and 4a are not like terms
2a^2 + 3a^2 are like terms
2a and 3a^2 are not like terms
3ab and 4ba are also like terms...even though the variables are switched
6b^2a and 6a^2b are not like terms
3 0
3 years ago
Read 2 more answers
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