Answer:
0.9968
Step-by-step explanation:
Given that:
P of being correct = 0.5 (since there are only 2 options in each question with only one bring correct).
1 - p = 1 - 0.5 = 0.5
Number of questions, n = 12
Probability that atleast 2 questions are correct
P(x ≥ 2) = p(x = 2) + p(x = 3) +... + p(x = 12)
P(x =x) = nCx * p^x * (1 - p)^(n - x)
The sun of the individual probabilities gives us the answer or we could use the binomial probability calculator :
Hence,
P(x ≥ 2) = 0.9968
Answer: Yes
Step-by-step explanation:
Since ABCD is a rectangle, , , , and are all right angles, and are thus all congruent because all right angles are congruent. Furthermore, because ABCD is a rectangle, we know that and . Because we are given that X, Y, Z, and W are midpoints, using the fact that halves of congruent segments are congruent, we can conclude that and that . As a result, we can conclude that by SAS, and thus by CPCTC, . Therefore, since the quadrilateral formed by the midpoints has four congruent sides, it must be a rhombus.
Do you mean like 81/100 or like 81/1
We know that the perimeter of a rectangle is 2(width)+2(length). We can multiply the length by 2 to find out how much remaining fencing we have, then divide that number by 2 to find the width.
15.5*2=31
170.5-31=139.5
139.5/2=69.75
A possible width is 69.75 feet.
Answer:5.25
Step-by-step explanation:
(7/8 of a mile) x (6 days)