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ValentinkaMS [17]
4 years ago
12

Math?

Mathematics
1 answer:
Mrac [35]4 years ago
7 0
An angle bisector is basically a bisector that divides an angle into two congruent parts. So, since one part of the angle is 61°, then the other part of the angle is also 61° by the definition of an angle bisector. The answer is C) Definition of Bisect. Hope this helps and have a great day!
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there are 4 trucks for every 5 cars in a parking lot. how many trucks and cars could be in the parking lot? A. 64 trucks and 80
Julli [10]

Answer:

A.

Step-by-step explanation:

64/4=16  80/5=16 They are multiplied by the same number so it is A

5 0
3 years ago
5 subtracted from 1/3 of 20
Bezzdna [24]

Answer:

1.666666667

Step-by-step explanation:

1/3 of 20 is 6.66666667

5-6.66666667 is -1.666666667

hope this helps :)

3 0
3 years ago
Read 2 more answers
Making high-stakes insurance decisions. The Journal of Economic Psychology (Sept. 2008) published the results of a high-stakes e
Andrej [43]

Answer:

a. P(24)=0.00007

b. P(23)=0.00018

c. There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

Step-by-step explanation:

The probabilities of two events ("fire"and "theft") are compared to the probabilities of a certain number of days of rain during July.

The probabilities of "fire"and "theft" are around P=0.0001, and we need to calculate if the probability of exactly 23 and exactly 24 days of rain July have approximately the same probability.

Rain frequencies for the months of July and August were shown to follow a Poisson distribution with a mean of 10 days per month.

The parameter then is:

\lambda=10

The probability of k days of rain is:

P(k)=\frac{10^ke^{-10}}{k!}

For 24 days, the probability is:

P(24)=\frac{10^{24}e^{-10}}{24!}=\frac{1*10^{24}*4.54*10^{-5}}{6.20*10^{23}}  = 0.00007

The probability of 23 days of rain is 27% less than P=0.0001.

For 23 days of rain, the probability is:

P(23)=\frac{10^{23}e^{-10}}{23!}=\frac{1*10^{23}*4.54*10^{-5}}{2.59*10^{23}}  = 0.00018

The probability of 23 days of rain is 76% more than P=0.0001.

There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

8 0
3 years ago
May someone help me with this problem? Thank you!
Aleks04 [339]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's find the value of given expression for x = 5 ~

\qquad \sf  \dashrightarrow \:3(3x + 5)

\qquad \sf  \dashrightarrow \:9x + 15

now, plug in the value of x as 5

\qquad \sf  \dashrightarrow \:9(5) + 15

\qquad \sf  \dashrightarrow \:45 + 15

\qquad \sf  \dashrightarrow \:60

so, the equivalent value is 60

6 0
2 years ago
Read 2 more answers
There are two spinners. The first spinner has three equal sectors labeled 1, 2, and 3. The second spinner has four equal sectors
zhuklara [117]
<h3>Answer: A) 1</h3>

=========================

Explanation:

Let's label each pair of outcomes as an ordered pair (x,y)

x = first spinner outcome

y = second spinner outcome

We have these 12 different possible combos

(1,3),   (1,4),   (1,5),   (1,6)

(2,3),  (2,4),  (2,5),  (2,6)

(3,3),  (3,4),   (3,5),  (3,6)

Focus on the third column where y = 5 for each (x,y) pair. Of this column only (2,5) has x be an even number. The other results in that column have x be odd.

Basically (1,5) is the only possible outcome if we want the first spinner to lan on an even number, and the second spinner to land on 5.

7 0
4 years ago
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