Triangles DEF and JKL can be proven to be congruent triangles based on:
C. ASA
E. AAS
F. LA
<h3>What is the ASA Congruence Theorem?</h3>
The ASA congruence theorem states that if two triangles that are have two pairs of corresponding congruent angles and a pair of corresponding included congruent sides, then both triangles are congruent to each other.
<h3>What is the
LA Congruence Theorem?</h3>
The LA congruence theorem states that two right triangles are congruent if they have a pair of congruent legs and a pair of congruent angles that are corresponding to each other.
<h3>What is the AAS Congruence Theorem?</h3>
The AAS congruence theorem states that two triangles with two pairs of congruent angles and a pair of congruent non-included sides are congruent.
From the image given, triangles DEF and JKL can be proven to be congruent triangles using the LA, AAS, and ASA congruence theorems.
Learn more about the LA, AAS, and ASA congruence theorems on:
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If you graph this scenario, the number of gallons of gas left will be on the y-axis while the number of miles traveled will be on the x-axis.
The line will be going downwards as the miles get longer. This is because the number of gallons of gas left will decrease as Janelle drives farther.
Assuming that Janelle initially had 10 gallons of gas and 1 mile consumes 1 gallon.
x y
0 10 As you can see, if you graph these coordinates,
1 9 the line of best fit will be going downwards.
2 8
3 7
4 6
5 5
6 4
7 3
8 2
9 1
10 0
Answer:
Multiply both sides by the reciprocal 4
Step-by-step explanation:
You have to isolate the variable 'n' and to do so, you must multiply both sides by the reciprocal: 4.
-12 mutliplied by 4 is -36.
1)first step
for the first inequation you need apply the following property, IXI < a
-a<x<a, them you must substitute 2x-3, of this form
-5<2x-3<5⇒ -5+3<2x-3+3<5+3⇒-2<2x<8⇒-2/2<2x/2<8/2⇒ -1<x<4,
the solution is
S1 =(-1,4)
2) For the second inequality apply the following property
IXI>a , x<-a or x >a , therefore
IX-2I>1 ⇒X-2 <-1 OR X-2> 1
X-2<-1⇒X-2+2<-1+2⇒ X< 1
OR
X-2>1⇒X>1+2⇒X>3
THE SOLUTION IS S2 = (-∞,1)∪(3,∞)