Question

The average score of all golfers for a particular course has a mean of 76 and a standard deviation of 5. suppose 100 golfers played the course today. find the probability that the average score of the 100 golfers exceeded 77. round to four decimal places.

Answer 1

Here, we first calculate the value of 't' and then go on calculating the probability that the t-value is more than calculated t-value, given the degree of freedom (d.f. = n-1). t.calc = (77-76)/(5/sqrt(100)) = 1/(1/2) = 2 P(x > 77) = P(t > 2, d.f. =99) = 0.0241= 2.41%