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masya89 [10]
3 years ago
7

F (5^4)m = 512, what is the value of m? 2 3 5 8

Mathematics
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer:

questions is wrong??

Step-by-step explanation:

5^4 is 625

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Help with this pls and thank u
stira [4]

Answer:

where is the question plsss tell me what you ask

8 0
3 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame
lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{207.9 - 208}{0.1678}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0
3 years ago
Roll the dice 18 times and record your results.
Roman55 [17]

Answer:

#    Tally

1:     ||||| (5)

2:    | (1)

3:    |||| (4)

4:    ||| (3)

5:    || (2)

6:    ||| (3)

3 0
3 years ago
Seven less than twice a number is no more than 77
irina1246 [14]
No because 77 is greater than the lowest number
4 0
3 years ago
Help please homework due tomorrow and I don't know how to do this
Furkat [3]
Number 1 is 0.2 and 0.4
number 2 is 0.53 and 0.56
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number 4 is 1/3
number 5 is a little bit before the 0.7 mark
number 6 is 62/100
4 0
3 years ago
Read 2 more answers
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