Answer:
It's 14.
Step-by-step explanation:
Google. ;)
Answer:
5 degrees
Step-by-step explanation:
We are given that during a science experiment
The temperature of a solution in a beaker 15 degrees below zero
The temperature of solution in a beaker 2 was opposite of the temperature in beaker 1
We have to determine the temperature of beaker 2.
It mean temperature of beaker 1 solution=-5 degrees
According to question
Temperature of beaker 2 solution =5 degrees
Hence, the temperature of solution in a beaker 2=5 degrees
The answer and equation is 17 - 19 = -2
1. You have that the rule for a number pattern is add 4 and the <span>first term is 7.
2. Let's call "n" to the number in the line where each student is. Then, you can express this as below:
4n+7
3. So, you have:
Student N°1=4(1)+7=11
</span> Student N°2=4(2)+7=15
Student N°3=4(3)+7=19
Student N°4=4(4)+7=23
Student N°5=4(5)+7=27
Student N°6=4(6)+7=31
Student N°7=4(7)+7=35
Student N°8=4(8)+7=39
<span>
What number should Jenna say?
The answer is: 39</span>
Answer:

Step-by-step explanation:
Given


Required
Determine the part left
The part left is calculated using:



Take LCM


