The number of the meals possible is 350.
The complete question is given below:-
A menu has 5 choices of appetizers, ten main courses, and seven desserts. How many meals are possible?
<h3 /><h3>What is the combination?</h3>
The arrangement of the different things or numbers in a number of ways is called the combination.
Given that:-
- A menu has 5 choices of appetizers, ten main courses, and seven desserts.
The number of the combination of the meals will be calculated as:-
N = 5 x 10 x 7
N = 350
Therefore the number of the meals possible is 350.
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Answer:
x = y/m - a
Step-by-step explanation:
divide both side by m
y/m = x + a
subtract a from both sides
y/m - a = x
switch sides.
x = y/m - a
Answer:
-40
Step-by-step explanation:
Try rearranging and factoring -8y-2c-2b-8x-2a:
This is equal to -8(x + y) -2(a + b + c).
Since x + y = 7, we have:
-8(7) -2(a + b + c)
and since a + b + c = 8, we end up with:
-56 - 2(8), or
-56 - 16 = -40
For your first question the answer is C(-2) and your next question the answer is A(-28)
Answer:
x =(-4-√136)/6=(-2-√ 34 )/3= -2.610
or
x =(-4+√136)/6=(-2+√ 34 )/3= 1.277
Step-by-step explanation:
