1. Round 50.75 to 50 and 0.18 to 0.20.
50 x 0.2 = 10
2) Round 96 to 100 and 0.499 to 0.5
100 divided by 0.5 = 50
3a) Round 8.2 to 8, 6.7 to 7, and 0.46 to 0.50
8 x 7 divided by 0.50 = 112
3b) Round 23.4 to 20, 13.9 to 10, and 0.18 to 0.20
20 x 10 divided by 0.20 = 2,000
Answer:
x1=3 x2=-5
BUT x1=3 is not an answer because it doesnt respects the range on the original ecuation, so x2=-5 is the solution
Step-by-step explanation:
Answer:
5.545
Step-by-step explanation:
This problem can be easily solved by using the law of cosines, which relates the lengths of the sides of a triangle to the cosine of one of its angles.
in this case, the formula can be applied in the following way
a^2 = b^2 + c^2 - 2*b*c*cos(α)
Where
a,b,c are each of the sides of the triangle,
α is the angle between sides b and c
(See attached picture)
If we use the formula we get
a^2 = (9)^2 + (6)^2 - 2*(9)(6)*cos(37°)
a^2 = 81 + 36 - 86.2526
a^2 = 30.747
a = sqrt(30.747)
a = 5.545
6n - 13 = 27
6n = 27 + 13
6n = 40
n = 40/6
n = 6 2/3
Answer: n = 6 2/3
2+3=5 and 4+1.5=2SO BY ADDIDING IS 9