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2 years ago

Can someone help me out please:(:(

Mathematics

1 answer:

patriot [66]2 years ago

8 0

Answer:

$\large\boxed{\sqrt{20}-\sqrt{80}=-2\sqrt5}$

Step-by-step explanation:

$\text{Use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{20}=\sqrt{4\cdot5}=\sqrt4\cdot\sqrt5=2\sqrt5\\\\\sqrt{80}=\sqrt{16\cdot5}=\sqrt{16}\cdot\sqrt5=4\sqrt5\\\\\sqrt{20}-\sqrt{80}=2\sqrt5-4\sqrt5=(2-4)\sqrt5=-2\sqrt5$

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3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

1. 5 in and 1/3 in

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$l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2$

3. 5/2 in and 4/3 in

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Let

$l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2$

Hence,

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

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Keywords: Rectangle, Area

Learn more about rectangles at:

#LearnwithBrainly

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Answer:

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1 year ago

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Answer:

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Step-by-step explanation:

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Answer:

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