Answer:
7/33 = 21 repeating and I'm pretty sure the question wants you to write it as an improper fraction. so your answer would be 40/33
Step-by-step explanation:
R^4-2(r-14)>0
r^4-2r+28>0
r^4-2r+28=0
There is no real solution but there is all real numbers
:)
For this case we have that by definition, the perimeter of the quadrilateral shown is given by the sum of its sides:
Let "p" be the perimeter of the quadrilateral, then:
![p = 7 + y + 7 + x\\p = 7 + 7 + x + y\\p = 14 + x + y](https://tex.z-dn.net/?f=p%20%3D%207%20%2B%20y%20%2B%207%20%2B%20x%5C%5Cp%20%3D%207%20%2B%207%20%2B%20x%20%2B%20y%5C%5Cp%20%3D%2014%20%2B%20x%20%2B%20y)
So, the perimeter of the figure is: ![14 + x + y](https://tex.z-dn.net/?f=14%20%2B%20x%20%2B%20y)
Answer:
![p = 14 + x + y](https://tex.z-dn.net/?f=p%20%3D%2014%20%2B%20x%20%2B%20y)
Answer:
do you still need help?
Step-by-step explanation: