Given:
Square pyramid with lateral faces.
646 ft wide at the base.
350 ft high.
Because of the term lateral faces, we need to get the lateral area of the square pyramid.
Lateral Area = a √a² + 4 h² ; a = 646 ft ; h = 350 ft
L.A. = 646 ft √(646ft)² + 4 (350ft)²
L.A. = 646 ft √417,316 ft² + 4 (122,500 ft²)
L.A. = 646 ft √417,316 ft² + 490,000 ft²
L.A. = 646 ft √907,316 ft²
L.A. = 646 ft * 952.53 ft
L.A. = 615,334.38 ft²
Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
Answer:
525 I think correct me if im wrong
Step-by-step explanation:
Step-by-step explanation:
2/3 gallons is empty
1/3 gallons is filled
so
3*1/3= 1
1 gallon filled
