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3 years ago

Describe how the graph of y=|x| – 4 is like the graph of y= |x| – 4 and how it is different.

1 answer:

5 0

If we were to subsitute the points and graph the equation we would notice that the shape is the same for both: a 45 degree angle line that goes upleft and up right
the graph of y=|x| looks like a right angle corner that is facing up that is ballancing on the point (0,0)
the graph of y=|x|-4 is the same except that the graph is shifter 4 units to the right ie. the point ofo the graph/rightangle is on point (4,0)

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Find the value of 216m³ - 8n³ if 6m - 2n=0 and mn=12

mestny [16]

Answer:

Step-by-step explanation:

Given that,

6m - 2n=0

=>6m=2n

=>n=3m [divide both side by 2]

& mn=12

Now,

216c - 8n³

= 216m³- 8(3m)³

=216m³- 8 .27m³

=216m³- 216m³

6 0

3 years ago

5 Find 6 in Surface Area

iVinArrow [24]

Answer:

8 x 6 = 48

48 divided by 2 = 24

24 x 2 = 48

10 x 12 = 120

120 x 2 = 240

8 x 12 = 96

Add all given areas:

48 + 96 + 240 = 384 in2 is your answer.

3 0

2 years ago

What is the area of the sector with a central angle of 97 degrees and a diameter of 10cm

vampirchik [111]

Answer:

21. 162 (rounded to nearest thousandth)

Step-by-step explanation:

Area of a sector: (degree/360) (pi*radius^2)

degree given= 97

radius= diameter/2 = 5

(97/360) (pi*5^2)

(97/360) (pi*25) = 21.16211718

4 0

3 years ago

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$