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Marina86 [1]
2 years ago
9

What operation would you use to covert yards and feet

Mathematics
2 answers:
lakkis [162]2 years ago
7 0

Answer:

Step-by-step explanation:

Leto [7]2 years ago
3 0
You would multiply, because there are 1 yards in 3 feet.
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My question is when multiplying scientific notations, after taking say, (8.2 * 4.5) and (10^9 * 10^-5) are you multiplying the 8
Kazeer [188]

Answer:you are adding them

Step-by-step explanation:

6 0
2 years ago
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The minimum value of Y in the equation y = x2 - 6x + 8
murzikaleks [220]

Given

y=x^2-6x+8

To obtain the minimum value of y, we first take the derivative of y

The derivative of y is:

y^{\prime}=2x-6

Equating

y^{\prime}\text{ = 0}

gives the minimum value we require.

Doing that, we have:

2x-6=0

So that

\begin{gathered} 2x=6 \\ x=\frac{6}{2} \\ =3 \end{gathered}

Therefore, the minimum value is x = 3

8 0
1 year ago
Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro
Ugo [173]

Answer:

Side\ B = 6.0

\alpha = 56.3

\theta = 93.7

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with \alpha, \beta, \theta

[See Attachment for Triangle]

A = 10cm

C = 12cm

\beta = 30

What the question is to calculate the third length (Side B) and the other 2 angles (\alpha\ and\ \theta)

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

B^2 = A^2 + C^2 - 2ABCos\beta

Substitute: A = 10,  C =12; \beta = 30

B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30

B^2 = 100 + 144 - 240*0.86602540378

B^2 = 100 + 144 - 207.846096907

B^2 = 36.153903093

Take Square root of both sides

\sqrt{B^2} = \sqrt{36.153903093}

B = \sqrt{36.153903093}

B = 6.0128115797

B = 6.0 <em>(Approximated)</em>

Calculating Angle \alpha

A^2 = B^2 + C^2 - 2BCCos\alpha

Substitute: A = 10,  C =12; B = 6

10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 180 - 144 *Cos\alpha

Subtract 180 from both sides

100 - 180 = 180 - 180 - 144 *Cos\alpha

-80 = - 144 *Cos\alpha

Divide both sides by -144

\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}

\frac{-80}{-144} = Cos\alpha

0.5555556 = Cos\alpha

Take arccos of both sides

Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)

Cos^{-1}(0.5555556) = \alpha

56.25098078 = \alpha

\alpha = 56.3 <em>(Approximated)</em>

Calculating \theta

Sum of angles in a triangle = 180

Hence;

\alpha + \beta + \theta = 180

30 + 56.3 + \theta = 180

86.3 + \theta = 180

Make \theta the subject of formula

\theta = 180 - 86.3

\theta = 93.7

5 0
3 years ago
An office spends $375.00 per month on office supplies.
podryga [215]

Answer:

$51 saved.

Step-by-step explanation:

Well 12% of $425 is found by multiplying

(.12)(425) = $51 saved.

8 0
3 years ago
Explain how to write the explicit rule for the arithmetic sequence from the given information
Alexxx [7]
The rule is to put them in order
6 0
3 years ago
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