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2 years ago

8

One exterior angle of a regular polygon measures 30 degrees. How many sides does the polygon have?

1 answer:

wolverine [178]2 years ago

5 0

360/30 = 12 sides. the exterior angles of ANY polygon has a sum of 360 degrees

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Which shows the equation in point-slope form of the line passing through the given point with the given slope?

avanturin [10]

<h2>SOLVING</h2>

$\Large\maltese\underline{\textsf{A. What is Asked}}$

Find the point-slope equation of the line, with the info given

$\Large\maltese\underline{\textsf{This problem has been solved}}$

Formula used, $\bf y-y1=m(x-x1)$

$\bf y-5=13(x-0)}$ | result

$\rule{300}{1.7}$

$\boxed{\bf aesthetic\not101}}$

3 0

1 year ago

A right rectangular prism is 5 1/4 in. wide, 12 1 2 in. long, and 4 in. tall.

lozanna [386]

Answer: $V = 262\frac{1}{2}$ $cm^{3}$

Step-by-step explanation:

$V = LWH$

$V = 5\frac{1}{4}$ X $12\frac{1}{2}$ X 4

$V = \frac{21}{4}$ X $\frac{25}{2}$ X $\frac{4}{1}$

$V = \frac{525}{2}$

$V = 262\frac{1}{2}$ $cm^{3}$

7 0

3 years ago

Jack's mother gave him 50 chocolates to give to his friends at his birthday party. He gave 3 chocolates to each of his friends a

djverab [1.8K]

50 = 3x + 2

50 - 2 = 3x

48 = 3x

48/3 = 3x/3

16 = x

Jack has 16 friends.

4 0

2 years ago

Read 2 more answers

If csc x = −5, find csc(−x) find the period and horizontal shift

ella [17]

Answer:

$\csc (-x) = - \csc x = - ( - 5) = 5$

Period is 2π

Horizontal shift = 0

Step-by-step explanation:

We know that $\sin (-x) = - \sin x$ and as $\csc x = \frac{1}{\sin x}$ , so, we can write $\csc (-x) = - \csc x$

Therefore, the if $\csc x = - 5$ then $\csc (-x) = - \csc x = - ( - 5) = 5$ (Answer)

Now, the period of $\csc x$ is 2π, hence the period of $\csc (- x)$ is also 2π. (Answer)

Again. $\csc ( - x) = \csc (-x + 0)$ , hence, the horizontal shift of $\csc (- x)$ is 0. (Answer)

6 0

3 years ago

Help please..............

Anarel [89]

I would say answer chose C

8 0

3 years ago

Read 2 more answers