All categories

3 years ago

What's $27.64×3 = please help

Mathematics

2 answers:

aleksandr82 [10.1K]3 years ago

5 0

$27.64×3 =82.92 answer=$82.92

krek1111 [17]3 years ago

4 0

The answer is $82.92

You might be interested in

On Monday, Sam's Pizza sold 40 large

Tanzania [10]

Answer:

$1,365

Step-by-step explanation:

Large Pizza: 40*12= $480

Medium Pizza: 57*10= $570

Small Pizza: 35*9= $315

480+570+315= $1,365

4 0

3 years ago

7,000 mg = how many grams

Gnom [1K]

7 grams. 1,000 mg is equivalent to one gram.

5 0

3 years ago

Determine the values of the constants r and s such that i(x, y) = x rys is an integrating factor for the given differential equa

garri49 [273]

$\underbrace{y(7xy^2+6)}_{M(x,y)}\,\mathrm dx+\underbrace{x(xy^2-1)}_{N(x,y)}\,\mathrm dy=0$

For the ODE to be exact, we require that $M_y=N_x$ , which we'll verify is not the case here.

$M_y=21xy^2+6$
$N_x=2xy^2-1$

So we distribute an integrating factor $i(x,y)$ across both sides of the ODE to get

$iM\,\mathrm dx+iN\,\mathrm dy=0$

Now for the ODE to be exact, we require $(iM)_y=(iN)_x$ , which in turn means

$i_yM+iM_y=i_xN+iN_x\implies i(M_y-N_x)=i_xN-i_yM$

Suppose $i(x,y)=x^ry^s$ . Then substituting everything into the PDE above, we have

$x^ry^s(19xy^2+7)=rx^{r-1}y^s(x^2y^2-x)-sx^ry^{s-1}(7xy^3+6y)$
$19x^{r+1}y^{s+2}+7x^ry^s=rx^{r+1}y^{s+2}-rx^ry^s-7sx^{r+1}y^{s+2}-6sx^ry^s$
$19x^{r+1}y^{s+2}+7x^ry^s=(r-7s)x^{r+1}y^{s+2}-(r+6s)x^ry^s$
$\implies\begin{cases}r-7s=19\\r+6s=-7\end{cases}\implies r=5,s=-2$

so that our integrating factor is $i(x,y)=x^5y^{-2}$ . Our ODE is now

$(7x^6y+6x^5y^{-1})\,\mathrm dx+(x^7-x^6y^{-2})\,\mathrm dy=0$

Renaming $M(x,y)$ and $N(x,y)$ to our current coefficients, we end up with partial derivatives

$M_y=7x^6-6x^5y^{-2}$
$N_x=7x^6-6x^5y^{-2}$

as desired, so our new ODE is indeed exact.

Next, we're looking for a solution of the form $\Psi(x,y)=C$ . By the chain rule, we have

$\Psi_x=7x^6y+6x^5y^{-1}\implies\Psi=x^7y+x^6y^{-1}+f(y)$

Differentiating with respect to $y$ yields

$\Psi_y=x^7-x^6y^{-2}=x^7-x^6y^{-2}+\dfrac{\mathrm df}{\mathrm dy}$
$\implies\dfrac{\mathrm df}{\mathrm dy}=0\implies f(y)=C$

Thus the solution to the ODE is

$\Psi(x,y)=x^7y+x^6y^{-1}=C$

4 0

3 years ago

Which statements are true? Select MORE THAN ONE correct answer.

DochEvi [55]

Statements 1 and 4 are correct. Let me know if you need more of an explanation. :)

7 0

3 years ago

Read 2 more answers

PLEASE, ANSWER WILL GIVE BRAINLIEST

balu736 [363]

0.30 • 18 = 5.4
0.30 • 40 = 12
0.30 • 9 = 2.7
0.30 • 70 = 21
0.30 • 48 = 14.4
0.30 • 26 = 7.8
0.30 • 14 = 4.2
Add the sums together which would be 67.5
Subtract $100 from $67.5 and that would be $32.5

Answer: $32.50 change

7 0

3 years ago