X=number of boys
y=number of girls.
We can suggest the following system of equations:
x+y=33
x/y=3/8
We solve this system of equations by substitution method.
x/y=3/8 ⇒x=3y/8
(3y/8)+y=33
least common multiple=8
3y+8y=33*8
11y=33*8
y=(33*8)/11
y=3*8
y=24
x+y=33
x+24=33
x=33-24
x=9
number of boys /total number of students=9/33=3/11
There are 9 boys and 24 girls in the class.
Answer: C: 9. since 3/11 of the students are boys.
Answer:
i don't know I have the same problem
The answer to this problem situation would be D.
To solve this problem you would simply divide 1 by 6 (the line between the 1 and 6 in the fraction is a division sign with the denominator always out and the numerator in)
1) 1÷6= 0.1666666666667
Now you traditionally and usually would round up but if the direction says otherwise then round down.
2) 0.17
And 0.17 would be your final answer!
