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dusya [7]
3 years ago
11

In a classroom of 33 students, the ratio of boys to girls is 3:8. How many boys are in the class?

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
7 0

the answer is 9

i'm only writing more because its making me or else i can't post this. I need the points badly! so... yeah... also thanks to the person who posted before me because i thought you were wrong until i read the step by step

hope you pass your Imagine Math lesson or whatever program you are doing!

good luck!

--- a weaboo who really wants to be an anime character, and is also in love with the show Yuri!!! on ICE

Hunter-Best [27]3 years ago
3 0
X=number of boys
y=number of girls.

We can suggest the following system of equations:
x+y=33
x/y=3/8

We solve this system of equations by substitution method.
x/y=3/8       ⇒x=3y/8

(3y/8)+y=33
least common multiple=8
3y+8y=33*8
11y=33*8
y=(33*8)/11
y=3*8
y=24

x+y=33
x+24=33
x=33-24
x=9

number of boys /total number of students=9/33=3/11

There are 9 boys and 24 girls in the class. 

Answer: C: 9. since 3/11 of the students are boys. 

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Answer:

a. N=25

b. X[bar]= 60.52

c. Y[bar]= 106.72

d. SSx= 115.24

e. ∑X*∑Y = 4036684

f. SSxy= 202020.3296

g. √(SSx*SSy)= 449.46

Step-by-step explanation:

Hello!

Using the attached data you need to calculate some statistics.

a) N

The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.

b.

The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52

∑X is listed in the second table.

c.

The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72

∑Y is listed in the second table.

d.

Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24

e.

∑X*∑Y =1513*2668= 4036684

f.

SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296

g.

√(SSx*SSy)= √(115.24*1753)= 449.46

I hope you have a SUPER day!

3 0
3 years ago
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