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loris [4]
3 years ago
8

I need help I need help I need help

Mathematics
2 answers:
IgorLugansk [536]3 years ago
6 0
What's next oh I also. like using ixl
Leona [35]3 years ago
5 0

Answer:

no

Step-by-step explanation:

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How do I study for a big math test? any tips on how to study I'm a visual learner.
Nastasia [14]

Honestly? Just review your notes and try to work out the problems yourself before taking a look at the answer. You can also google specific topics that the test will cover and try the practice problems.

3 0
3 years ago
Read 2 more answers
A factory makes widgets x and gadgets y. Widgets cost $3 and gadgets cost $5 each to make. The boss wants at least 10 widgets an
IgorLugansk [536]

Answer:

$130

Step-by-step explanation:

Because you multiple 3 and 10 to get 30 and 5 and 20 to get 100 and then add 100+30 to get 130 and that would be 130 dollars in one day

6 0
3 years ago
Write the equation of the directrix of the conic section shown below.
Aneli [31]
<span>The equation of the directrix of the conic section </span>y^2 + 16y + 4x + 4 = 0 is x = 16.
3 0
3 years ago
How many different integers between $100$ and $500$ are multiples of either $6,$ $8,$ or both?
nirvana33 [79]
We need to find the number of integers between 100 and 500 that can be divided by 6, 8, or both. Now, to do this, we must as to how many are divisible by 6 and how many are multiples of 8.

The closest number to 100 that is divisible by 6 is 102. 498 is the multiple of 6 closest to 500. To find the number of multiple of 6 from 102 to 498, we have

n = \frac{498-102}{6} + 1
n = 67

We can use the same approach, to find the number of integers that are divisible by 8 between 100 and 500. 

n = \frac{496-104}{8} + 1
n = 50

That means there are 67 integers that are divisible by 6 and 50 integers divisible by 8. Remember that 6 and 8 share a common multiple of 24. That means the numbers 24,  48, 72, 96, etc are included in both lists. As shown below, there are 16 numbers that are multiples of 24.

n = \frac{480-120}{24} + 1
n = 16

Since we counted them twice, we subtract the number of integers that are divisible by 24 and have a final total of 67 + 50 - 16 = 101. Hence there are 101 integers that are divisible by 6, 8, or both.

Answer: 101


8 0
3 years ago
Permudahkan setiap yang berikut
neonofarm [45]

Answer:

Step-by-step explanation:

\frac{4^{2}*4^{5} }{(4^{6})^{2}}=\frac{4^{2}*4^{5} }{4^{12}}\\\\=4^{2+5-12}=4^{-5}\\\\ =\frac{1}{4^{5}}

5 0
3 years ago
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