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maks197457 [2]
3 years ago
11

How do I study for a big math test? any tips on how to study I'm a visual learner.

Mathematics
2 answers:
jeyben [28]3 years ago
7 0
I would rewrite your notes, that helps me remember. Or if you dont like writing, search up videos on the subjects and find problems online to solve.
Nastasia [14]3 years ago
3 0

Honestly? Just review your notes and try to work out the problems yourself before taking a look at the answer. You can also google specific topics that the test will cover and try the practice problems.

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If A = 50 degrees, B = 62 degrees, and a = 4, find b.<br><br> Round to the nearest tenth.​
Phoenix [80]
<h3>Answer:  4.6</h3>

=================================================

Work Shown:

Use the law of sines

b/sin(B) = a/sin(A)

b/sin(62) = 4/sin(50)

b = sin(62)*4/sin(50)

b = 4.61042489526572

b = 4.6

Make sure your calculator is in degree mode.

8 0
3 years ago
A drawer contains white socks and black socks only.
crimeas [40]

Answer:

36 black socks

Step-by-step explanation:

white socks: black socks

1  :3

We have 12 white socks so we multiply each term by 12

1*12 : 3*12

12:36

We have 36 black socks

5 0
3 years ago
Write 3/60 as a fraction in its simplest form
mart [117]

Answer:

\frac{1}{20}

Step-by-step explanation:

\frac{3}{60}=\frac{1}{20}

To get \frac{1}{20} you needed to divide the numerator and denominator by 3.

5 0
4 years ago
Read 2 more answers
BRAINLIEST FOR WHOEVER ANSWERS FIRST!!!!
Fofino [41]

Answer:

x = 34

Step-by-step explanation:

ΔABD and ΔBCD are both isosceles triangles

In ΔABD

AB =AD, hence ∠ABD = ∠ADB ( base angles are equal )

∠ABD = \frac{180-44}{2} = \frac{136}{2} = 68°

∠DBC = 180° - 68° = 112° ( straight angle )

∠BCD = x = \frac{180-112}{2} = \frac{68}{2} = 34


4 0
3 years ago
A kite is flying above the ground
andriy [413]

The height of the kite above the ground is 90.63 feet.

<u>Step-by-step explanation:</u>

The angle of elevation of the kite is (θ) 65°.

The distance between the kite and its end is (hypotenuse)100 feet.

To find the height (x) of the kite flying above the ground.

we know that sin(θ) =\frac{height}{hypotenuse}.

sin 65°=\frac{x}{100} .

sin 65° =  0.90631.

0.90631 ×100=x.

90.63=x.

∴The height of the kite above the ground is 90.63 feet.

8 0
3 years ago
Read 2 more answers
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