Question

Solve each equation by factoring 16x²-9=0

Answer 1

We see that this is difference of 2 perfect squares
a^2-b^2=(a+b)(a-b) so
(4x)^2-3^2=(4x-9)(4x+9)
so we set each to zero
4x-9=0
add 9
4x=9
divide 4
x=9/4


4x+9=0
subtract 9
4x=-9
divide 4
x=-9/4

x=-9/4 or 9/4

Answer 2

For this question you should first add +9 on both sides of the equation so you will have:
16x^2 = 9 
and then you should divide both sides by 16:
x^2 = 9/16 
and the square root of both sides will give you:
x = 3/4 and -3/4 :))))
i hope this is helpful
have a nice day