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Sergeeva-Olga [200]
4 years ago
13

a five inch bamboo shoot doubles in height every three days. If the equation y=ab to the x power, where x represents the number

of doubling periods what are the values of a and b
Mathematics
1 answer:
PtichkaEL [24]4 years ago
5 0
This question was once asked before so I will put it here.

The correct answer for the question that is being presented above is this one: "x = 2; a = 5; b = 3" A 5 inch tall bamboo shoot doubles in height every 3 days. If the equation y=ab^x, where x is the number of doubling periods, represents the height of the bamboo shoot.

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A cargo truck that weighs 1 ton is going to cross a bridge. The bridge capacity has a limit of 5,000 pounds. If the cargo truck
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Answer:A

Step by step explanation: if a ton =2000 and the truck is only carrying a ton. It is not exceeding the limit that the bridge can hold which is 5000 lbs (2 1/2 tons)
3 0
3 years ago
Giving Brainliest, easy question
eimsori [14]

Answer:

the 2nd answer

Step-by-step explanation:

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4 0
3 years ago
Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

4 0
4 years ago
Read 2 more answers
-136=-8(7-2x) what is the value of x
serg [7]

Answer:

x=-5

Step-by-step explanation:

hope i helped

5 0
3 years ago
Please answer this asap
Ymorist [56]
30yd it is ur welcome have a nice nice day bteee
8 0
3 years ago
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