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3 years ago

consider the triangles shown below. which of the following relationship is needed to prove that ABD ...

Mathematics

1 answer:

Brrunno [24]3 years ago

5 0

A. is the answer.

the 2 triangls have AD = AC

and AB as a common side. therefore the triangls are congruent.

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Łatwy ułamek 36/7-3/5-4/10

Free_Kalibri [48]

Answer:

$4 \frac{1}{7}$

Step-by-step explanation:

$\frac{36}{7} - \frac{ 3}{5} - \frac{4}{10} \\ \\ lcm \: \: is \: \: 70 \\ \\ \frac{360 - 42 - 28}{70} \\ = \frac{290}{70} \\ = \frac{29}{7} \\ = 4 \frac{1}{7}$

hope this helps you.

Can I have the brainliest please?

5 0

3 years ago

1. The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag a

lapo4ka [179]

Answer:

Option d :18 bags of chips and 6 jars of salsa

Step-by-step explanation:

Given : The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag and salsa, which costs $4 per jar. The chips & salsa budget you are given totals $60.

Inequality : $2.5x+4y\leq 60$

Solution :

x represents chips

y represents salsa

Option a: 10 bags of chips and 2 jars of salsa

so, x = 10 and y =2

Putting values in inequality

$2.5(10)+4(2)\leq 60$

$25+8\leq 60$

$33\leq 60$

Hence it is correct.

Option b : 20 bags of chips and 2 jars of salsa

so, x = 20 and y =2

Putting values in inequality

$2.5(20)+4(2)\leq 60$

$50+8\leq 60$

$58\leq 60$

Hence it is correct.

Option c : 14 bags of chips and 5 jars of salsa

so, x = 14 and y =5

Putting values in inequality

$2.5(14)+4(5)\leq 60$

$35+20\leq 60$

$55\leq 60$

Hence it is correct.

Option d :18 bags of chips and 6 jars of salsa

so, x = 18 and y =6

Putting values in inequality

$2.5(18)+4(6)\leq 60$

$45+24\leq 60$

$69\geq 60$

Hence it is not correct since it violates the inequality

4 0

3 years ago

Read 2 more answers

What is the solution to the following equation?

o-na [289]

The Answer is A.

To solve the equation for x you need to find a, b and c of the quadratic then apply the quadratic formula resulting in that answer.

7 0

3 years ago

Todea what did one pencil say to another mathematics algebra order of operations answer

Serjik [45]

Part 1

$6- \frac{18-3^2}{4+(2-3)} =6- \frac{18-9}{4+(-1)} \\ \\ =6- \frac{9}{4-1} =6- \frac{9}{3} =6-3 \\ \\ =3$

Part 2

$7-8\div4(3^2-1)=7-8\div4(9-1) \\ \\ =7-8\div4(8)=7-8\div32=7- \frac{1}{2} \\ \\ =6 \frac{1}{2} = \frac{13}{2}$

Part 3

$2-2(2-5)^2+3^2=2-2(-3)^2+9 \\ \\ =2-2(9)+9=2-18+9=-7$

Part 4

$(5^2-9\cdot3)^2-11=(25-27)^2-11 \\ \\ =(-2)^2-11=4-11=-7$

Part 5

$[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\ \\ =(1-5)\cdot4=-4\cdot4=-16$

Part 6

$12-11\cdot2+16\div8=12-22+2 \\ \\ =-8$

Part 7

$-5+1\cdot3-(7-2^3)=-5+3-(7-8) \\ \\ =-2-(-1)=-2+1=-1$

Part 8

$8+2\cdot3-14\div7=8+6-2 \\ \\ =12$

Part 9

$(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\ \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\ \\ =36+4=40$

Part 10

$7+(2-3^2)\cdot5=7+(2-9)\cdot5 \\ \\ =7+(-7)\cdot5=7+(-35)=7-35 \\ \\ =-28$

Part 11

$3-2[2^3+(-1)^3]=3-2[8+(-1)] \\ \\ =3-2(8-1)=3-2(7)=3-14 \\ \\ -11$

Part 12

$18+6\div3(2^2+5)=18+6\div3(4+5) \\ \\ =18+6\div3(9)=18+6\div27=18+ \frac{2}{9} \\ \\ =18 \frac{2}{9}$