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4 years ago

Helpp meee pleaseee:/

Mathematics

2 answers:

NNADVOKAT [17]4 years ago

7 0

I believe you are right! Good job it is -910

tensa zangetsu [6.8K]4 years ago

3 0

Your correct the answer is B.

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Complete the table of inputs and outputs for the given function. g(x)=-4x-1

Radda [10]

Answer:

(x, y) = (-2, 7), (0, -1), (3, -13), (-1, 3)

Step-by-step explanation:

To fill in the y-values, you need to put the x-value in the equation and evaluate.

for x=0

y = -4(0) -1 = -1

for x=-1

y = -4(-1) -1 = 4 -1 = 3

To fill in the x-values, we can solve for x and then do as we did above.

y = -4x -1

y +1 = -4x . . . . add 1

-(y +1)/4 = x . . . divide by -4

for y=7

x = -(7 +1)/4 = -2

for y=-13

x = -(-13+1)/4 = -(-12/4) = 3

Then the table is ...

$\boxed{\begin{array}{cc}x&g(x)\\-2&7\\0&-1\\3&-13\\-1&3\end{array}}$

7 0

2 years ago

Given the equation −2x − 13 = 8x + 7, which order of operations completely solves for x?

Marina CMI [18]

Answer:

Subtract 8x, then add 13, lastly divide by −10

6 0

3 years ago

Read 2 more answers

The admission fee at the steamboat springs hot air balloon festival is $1.50 for children and $4.00 for adults. On a certain day

GaryK [48]

Answer:

Number of child tickets = 800

Number of adult tickets = 330

Step-by-step explanation:

Let c = number of child tickets

and a= the number of adult tickets.

We are given:

The admission fee at the steamboat springs hot air balloon festival is $1.50 for children and $4.00 for adults.

On a certain day, 1,130 enter the festival and 2, 520 is collected.

Making equations:

$c+a=1130$ (because total people entered are 1130, so adding number of adult and child tickets will give us total number of people)

$1.50c+4.00a=2520$ (because total money collected is 2520, so adding coat of adult and child tickets will give us total money)

Now, solving these equations simultaneously, we can find values of x and y

Let:

$c+a=1130--eq(1)\\1.50c+4.00a=2520--eq(2)$

From equation 1 find value of c and put it in eq(2)

$c+a=1130\\c=1130-a$

Putting value of c in eq(2)

$1.50c+4.00a=2520\\Put\:c=1130-a\\1.5(1130-a)+4a=2520\\1695-1.5a+4a=2520\\-1.5a+4a=2520-1695\\2.5a=825\\a=\frac{825}{2.5}\\a=330$

So, we get value of a = 330

Now, punting value of a in eq(1) to get value of c

$c+a=1130\\c+330=1130\\c=1130-330\\c=800$

So, we get value of c = 800

Therefore:

Number of child tickets = c= 800

Number of adult tickets = a = 330

4 0

3 years ago

2 factors that add to 6 but multiply to 60

hodyreva [135]

Answer:

The short answer is there isn’t.

Start by writing each of these as an expression:

x * y = 60

x + y = 7

Next, solve each for the same variable; in this case, y:

(x * y) / x = 60 / x

.: y = 60 / x

(x + y) - x = 7 - x

.: y = 7 - x

Next, replace y of the second expression to the first

y = 60 / x & y = 7 - x

.: 7 - x = 60 / x

Now, solve for x:

(7 - x) * x = (60 / x) * x

.: x * 7 - x^2 = 60

This is quadratic, so write it in the form of ax2 + bx + x = 0

(-1)x^2 + (7)x + (-60) = 0

.: a = -1, b = 7, c = -60

Finally solve for b:

x = (-b +- sqrt(b^2 - 4*a*c)) / 2a

.: x = (-7 +- sqrt(7^2 - 4*-1*-60)) / (2 * -1)

.: x = (-7 +- sqrt(49 - 240)) / -2

.: x = (-7 +- sqrt(-191)) / -2

The square root of a negative value is imaginary and thus there’s no real answer to this problem.

8 0

3 years ago

I have to factor polynomials by grouping

LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

Factor 6f3−8f2+20−15f

6f^3−8f^3−15f

=(3f−4)(2f2−5)

Answer:

(3f−4)(2f^2−5)

Find the group you want to factor, such as in the first parenthesis, you remove 3f from the whole equation, and end up with 3f-4. You take the end value, and group it with -5. You will then end up with 2f^2 -5.

Hope this Helps!

6 0

3 years ago