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ra1l [238]
3 years ago
10

I have to factor polynomials by grouping

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
6 0

Answer:

Step-by-step explanation:

Factor 6f3−8f2+20−15f

6f^3−8f^3−15f

=(3f−4)(2f2−5)

Answer:

(3f−4)(2f^2−5)

Find the group you want to factor, such as in the first parenthesis, you remove 3f from the whole equation, and end up with 3f-4. You take the end value, and group it with -5. You will then end up with 2f^2 -5.

Hope this Helps!

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Does anyone know the answer to this scale and unit conversion GED math problem? Thank you very much!
aliya0001 [1]

Answer:

Flour 5\dfrac{1}{2}\ c

Sugar 2\dfrac{2}{3}\ c

Butter 1\dfrac{1}{2}\ c

Eggs 2

Baking powder 7\ t

Vanilla extract 3\ t

Step-by-step explanation:

There will be 16 people at the party. Each person will eat 3 cookies, so all people will eat 16\cdot 3=48 cookies.

Given cookie recipe makes 24 cookies, so to make 48 cookies you need

48:24=2 portions.

Thus,

              1 portion                      2 portions

Flour      2 \dfrac{3}{4}\ c               2\dfrac{3}{4}\cdot 2=2\cdot 2+\dfrac{3}{4}\cdot 2=4+\dfrac{3}{2}=4+1 \dfrac{1}{2}=5\dfrac{1}{2}\ c

Sugar    1\dfrac{1}{3}\ c                  1\dfrac{1}{3}\cdot 2=1\cdot 2+\dfrac{1}{3}\cdot 2=2+\dfrac{2}{3}=2\dfrac{2}{3}\ c

Butter    \dfrac{3}{4}\ c                  \dfrac{3}{4}\cdot 2=\dfrac{3}{2}=1\dfrac{1}{2}\ c

Eggs      1                           1\cdot 2=2

Powder 3\dfrac{1}{2}\ t                  3\dfrac{1}{2}\cdot 2=3\cdot 2+\dfrac{1}{2}\cdot 2=6+1=7\ t

Vanilla   1\dfrac{1}{2}\ t                  1\dfrac{1}{2}\cdot 2=1\cdot 2+\dfrac{1}{2}\cdot 2=2+1=3\ t

8 0
3 years ago
-15 + 8 = <br> A) -23 <br> B) -7 <br> C) 11 <br> D) 23
bagirrra123 [75]

Answer:

B) -7

Step-by-step explanation:

since since since there is more of the negative number then the positive number, the positive number gets canceled out.

6 0
3 years ago
Read 2 more answers
The table represents the height of a ball thrown up from the roof of a building, h(t), in meters, t seconds after it is thrown u
Anna [14]
• The ball is at the same height as the building between 8 and 10 seconds after it is thrown. TRUE - the height is zero somewhere in that interval, hence the ball is the same height from which it was thrown, the height of the roof of the building.

• The height of the ball decreases and then increases. FALSE - at t=2, the height is greater than at t=0.

• The ball reaches its maximum height about 4 seconds after it is thrown. TRUE - the largest number in the table corresponds to t=4.

• The ball hits the ground between 8 and 10 seconds after it is thrown. FALSE - see statement 1.

• The height of the building is 81.6 meters. FALSE - the maximum height above the building is 81.6 meters. Since the ball continues its travel to a distance 225.6 meters below the roof of the building, the building is at least that high.


1. TRUE
2. False
3. TRUE
4. False
5. False
9 0
3 years ago
Read 2 more answers
The volume of a rectangular prism is 2,058 cubic cm. The length of the prism is 3 times the width. The height is twice the width
liraira [26]
Let the width be w, length = 3w and height = 2w

Volume = length x width x height = w x 3w x 2w = 6w^3
6w^3 = 2,058
w^3 = 2,058/6 = 343
w = ∛343 = 7

width = 7 cm
8 0
3 years ago
Rita bought 6 boxes of chocolates. Each box cost $6.48. How much did she spend?
Elena L [17]

Answer:

38.88

Step-by-step explanation:

Take the price per box and multiply by the number of boxes

6.48*6 =38.88

3 0
3 years ago
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