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viva [34]
3 years ago
12

10 POINTS!!!! Give the center, radius, and equation of the circle in the graph.

Mathematics
2 answers:
aksik [14]3 years ago
7 0

Answer:

Below.

Step-by-step explanation:

The center is at (2, -3) and the radius is 2.

The general form for a circle is

(x - h)^2 + (y - k)^2 = r^2    where (h, k) is the center and r = the radius.

So here the equation is:

(x - 2)^2 + (y + 3)^2 = 4.

vitfil [10]3 years ago
5 0

Answer:

centre is 2,-3

radius is 2 units

Step-by-step explanation:

I dont know how to find the equation

above answers are also guesses.

hope u don't mind

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I need to find the area of the shaded region, can anyone explain how to do it? ​
vesna_86 [32]

Answer:

Step-by-step explanation:

JM is a diameter. 1/2 JM is the radius. 1/2 10 = 5

The radius is 5

The above statement is true if N is the center.

The semi circle has an area of pi r^2/2 = 5^2/2 * pi = 25/2 * pi

12.5 pi

The area of the other part is

(58/360) * pi * r^2 =

0.161 * pi * 5^2

0.161 * pi * 25

4.03 * pi

Now add these two parts together.

12.5pi + 4.03= 16.53 * pi.

That's one possible answer.

Another would be 16.53 * 3.14 = 51.897

If you have choices, list them.

5 0
3 years ago
Help?? Thanks so much
Ira Lisetskai [31]
A..........duh just read the sides of the graph
6 0
3 years ago
Find the distance CD rounded to<br> the nearest tenth.<br> C = (7,-4) and D = (-8,-5)<br> CD = [?]
quester [9]

Answer:

CD= 15.03

Step-by-step explanation:

x1=7, x2= -8

y1=-4, y2=-5

distance CD= √(x2- x1) 2+ (y2-y1)2

= √( -8-7)2 + [-5-(-4)]2

= √(15)2+ (-5+4)2

= √225+ (1)2

= √225+1

= √226

= 15.03

7 0
2 years ago
Find the average value of the function f(t)=cos13(5t)sin(5t) f(t)=cos13⁡(5t)sin⁡(5t) on the interval [4,10].
Vilka [71]
The average value is given by

\displaystyle\frac1{10-4}\int_4^{10}\cos^{13}5t\sin5t\,\mathrm dt

Setting y=\cos5t, you get \mathrm dy=-5\sin5t\,\mathrm dt, and the integral becomes

\displaystyle-\frac1{30}\int_{\cos20}^{\cos50}y^{13}\,\mathrm dy
=-\dfrac1{30}\dfrac{y^{14}}{14}\bigg|_{y=\cos20}^{y=\cos50}
=-\dfrac{\cos^{14}50-\cos^{14}20}{420}\approx-0.00145
6 0
3 years ago
INCREDIBLY URGENT!!
Gemiola [76]

Answer:

When you see a formula like this, try to operate, so you will see some identities sooner or later. In this case, we have a substraction identity:

\frac{cos ( \alpha  -  \beta )}{cos  \alpha cos  \beta }  =  \frac{cos   \alpha cos  \beta + sin \alpha sin  \beta }{cos  \alpha cos  \beta }  = 1 + tan α · tan β

Step-by-step explanation:

3 0
3 years ago
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