Answer:
Step-by-step explanation:
a)
P(f ) = probability of being female = .3
P(m ) Probability of being male = .7
P(s/m) = probability of having a smoker worker given that he is a male = .6
P(s/f) = probability of having a smoker worker given that he is a male = .4
p(s) = p(m) x p(s/m) + p(f) x P(s/f)
= .7 x .6 + .4 x .3
= .42 + .12
= .54
b )
p (m/s) = probability that this person will be a male,Given that this person is a smoker
p(m) x p(s/m) / [ p(m) x p(s/m) + p(f) x P(s/f) ]
= .7 x .6 / .7 x .6 + .4 x .3
= .42 / .54
= .78
c )
Probability of the person being a smoker and male
= .54 x .78 = .42
probability of a person being a male and non smoker = .7 - .42 = .28
probability of a person being a non smoker and female = .46 -.28 =.18
probability that person will be a smoker or a male
= 1 - (a person being a non smoker and female).
= 1 - .18
= .82 .
Your answer should be 33 m ^2
Answer:
Step-by-step explanation:
Diameter of cone = 16 in
Radius of cone r = 16/2 = 8 in
Height of cone h = 17.6 in
Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
