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alekssr [168]
3 years ago
10

Rename fraction 2/5 so you can add it to 11/25. Find the sum.

Mathematics
2 answers:
Slav-nsk [51]3 years ago
7 0
\frac{2}{5}+ \frac{11}{25}=x \\  \\  \frac{(5)2}{(5)5} + \frac{11}{25}  \\  \\  \frac{10}{25} + \frac{11}{25} \\  \\  \frac{10+11}{25} \\  \\ \boxed { \frac{21}{25}}
mestny [16]3 years ago
7 0
2/5 + 11/25

Find common denominator (25)

10/25 + 11/25

21/25

The sum of 2/5 and 11/25 is 21/25.


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If the area of a circle is 58 square feet, find the circumference
Blizzard [7]

Answer:

C≈27 feet

Step-by-step explanation:

A=πr²

A/π=r²

√A/π =r or –√A/π=r (refused)

then r =√(A/π) =√(58/π) =4.297829403 feet

C=2πr=2π(4.297829403)=27.00405856≈27 feet

7 0
3 years ago
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Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^5(+3)^0\\
2&+5&(2x)^4(+3)^1\\
3&+10&(2x)^3(+3)^2\\
4&+10&(2x)^2(+3)^3\\
5&+5&(2x)^1(+3)^4\\
6&+1&(2x)^0(+3)^5
\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^4(-3y)^0\\
2&+4&(2x)^3(-3y)^1\\
3&+6&(2x)^2(-3y)^2\\
4&+4&(2x)^1(-3y)^3\\
5&+1&(2x)^0(-3y)^4
\end{array}


\bf (3a+4b)^8\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(3a)^8(+4b)^0\\
2&+8&(3a)^7(+4b)^1\\
3&+28&(3a)^6(+4b)^2\\
4&+56&(3a)^5(+4b)^3\\
5&+70&(3a)^4(+4b)^4\\
6&+56&(3a)^3(+4b)^5\\
7&+28&(3a)^2(+4b)^6\\
8&+8&(3a)^1(+4b)^7\\
9&+1&(3a)^0(+4b)^8
\end{array}

and from there, you can simplify the elements of the expansion by combining the coefficients

like for example, the 7th element of (3a+4b)⁸ will then be 1032192a²b⁶
7 0
3 years ago
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12345 [234]
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Steps:
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5 0
3 years ago
Ethan Planted a tree that was 1.85 meters tall. Several years later, the tree is 5.30 meters tall. Which equation can be used to
Sergeu [11.5K]
Answer: B. 1.85 + x = 5.30

Explanation:

The starting height of the tree was 1.85 meters. To find the number of meters the tree grew, you would subtract the current height from the previous height.
5.30-1.85=x. This equation is the same as 1.85 + x = 5.30 if you switch the 5.30 and x.
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Rudik [331]

Answer:

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13=ab^0

Since anything to the zeroth power is 1, this yields:

a=13

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b=4

Hence, our b value is 4.

Therefore, our entire equation is:

y=13(4)^x

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3 years ago
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