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Tju [1.3M]
3 years ago
11

Which pair of angle measures satisfy the condition sin J = cos K?

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0
J = K = 45° or 315°
...........................................................
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A delivery truck is transporting boxes of two sizes: large and small. the combined weight of a large box and a small box is 60 p
sdas [7]

Let a = weight of large box in pounds

Let b = weight of small box in pounds

(1) 65a + 70b=4000

(2) a+b=60

Now we can simultaneously solve these equations.

a = 60 - b. Hence 65(60 - b) + 70b = 4000 So 3900 + 5b = 4000 and 100 = 5b hence b = 20.

SImilarly a = 40. Now we can verify too by putting in the calculated values.

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Which equation is equivalent to log (x+5) = 27
Tresset [83]

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(22+5)=27 or  (x+y)=27

Step-by-step explanation:

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sveta [45]

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What is the equation of this line?
QveST [7]

Answer:

y = (1/2)x - 3     Answer A is closest.  

Step-by-step explanation:

Two points on the line are (0, -3) and (4, -1).  Notice that I've intentionally chosen "nice" points whose coordinates are integers; this makes the math easier.  The point (1, -5/2) is also on the line if you want to use it, but the math's a bit more complicated.

Going from (0, -3) to (4, -1), x increases by 4 and y increases by 2.  Hence, the slope of this line is m = rise / run = 2/4, or m = 1/2.

The slope-intercept formula for the equation of a straight line is the most convenient to use here, since we can tell immediately from the graph that the y-intercept is (0, -3):

y = (1/2)x - 3

Answer A should be y = (1/2)x - 3 for improved legibility.  1 2 x is not correct as a way to express (1/2)x.

6 0
3 years ago
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The Ace Novelty company produces two souvenirs: Type A and Type B. The number of Type A souvenirs, x, and the number of Type B s
Molodets [167]

Answer:

  500 type A; 3500 type B

Step-by-step explanation:

The method of Lagrange multipliers can solve this quickly. For objective function f(x, y) and constraint function g(x, y)=0 we can set the partial derivatives of the Lagrangian to zero to find the values of the variables at the extreme of interest.

These functions are ...

  f(x,y)=4x+2y\\g(x,y)=2x^2+y-4

The Lagrangian is ...

  \mathcal{L}(x,y,\lambda)=f(x,y)+\lambda g(x,y)\\\\\text{and the partial derivatives are ...}\\\\\dfrac{\partial \mathcal{L}}{\partial x}=\dfrac{\partial f}{\partial x}+\lambda\dfrac{\partial g}{\partial x}=4+\lambda (4x)=0\ \implies\ x=\dfrac{-1}{\lambda}\\\\\dfrac{\partial \mathcal{L}}{\partial y}=\dfrac{\partial f}{\partial y}+\lambda\dfrac{\partial g}{\partial y}=2+\lambda (1)=0\ \implies\ \lambda=-2

  \dfrac{\partial\mathcal{L}}{\partial\lambda}=\dfrac{\partial f}{\partial\lambda}+\lambda\dfrac{\partial g}{\partial\lambda}=0+2x^2+y-4=0\ \implies\ y=4-2x^2\\\\\text{We know $\lambda$, so we can find x and y:}\\\\x=\dfrac{-1}{-2}=0.5\\\\y=4-2\cdot 0.5^2=3.5

Since x and y are in thousands, maximum profit is to be had when the company produces ...

  500 Type A souvenirs, and 3500 Type B souvenirs

3 0
3 years ago
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