I believe u would divide, 162 divided by 9= 18
It is a 1/221 chance of drawing an ace and a queen
5x+2/5=x-1/10
Convert 2/5 and -1/10 to equal fractions.
2/5= 4/10
5x+4/10= x-1/10
Subtract x on both sides.
4x+4/10= 1/10
Subtract 4/10 on both sides.
4x=-3/10
Divide both sides by 4.
x=-0.075
I hope this helps!
~kaikers
Answer:
possible values of 4th term is 80 & - 80
Step-by-step explanation:
The general term of a geometric series is given by
![a(n)=ar^{n-1}](https://tex.z-dn.net/?f=a%28n%29%3Dar%5E%7Bn-1%7D)
Where a(n) is the nth term, r is the common ratio (a term divided by the term before it) and n is the number of term
- Given, 5th term is 40, we can write:
![ar^{5-1}=40\\ar^4=40](https://tex.z-dn.net/?f=ar%5E%7B5-1%7D%3D40%5C%5Car%5E4%3D40)
- Given, 7th term is 10, we can write:
![ar^{7-1}=10\\ar^6=10](https://tex.z-dn.net/?f=ar%5E%7B7-1%7D%3D10%5C%5Car%5E6%3D10)
We can solve for a in the first equation as:
![ar^4=40\\a=\frac{40}{r^4}](https://tex.z-dn.net/?f=ar%5E4%3D40%5C%5Ca%3D%5Cfrac%7B40%7D%7Br%5E4%7D)
<em>Now we can plug this into a of the 2nd equation:</em>
<em>
</em>
<em />
<em>Let's solve for a:</em>
<em>
</em>
<em />
Now, using the general formula of a term, we know that 4th term is:
4th term = ar^3
<u>Plugging in a = 640 and r = 1/2 and -1/2 respectively, we get 2 possible values of 4th term as:</u>
![ar^3\\1.(640)(\frac{1}{2})^3=80\\2.(640)(-\frac{1}{2})^3=-80](https://tex.z-dn.net/?f=ar%5E3%5C%5C1.%28640%29%28%5Cfrac%7B1%7D%7B2%7D%29%5E3%3D80%5C%5C2.%28640%29%28-%5Cfrac%7B1%7D%7B2%7D%29%5E3%3D-80)
possible values of 4th term is 80 & - 80
Answer is quantom physics cant equate to the sum of the x