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ira [324]
3 years ago
11

Help please urgent!

Mathematics
1 answer:
myrzilka [38]3 years ago
8 0

Answer:

5

Step-by-step explanation:

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Hiw many 2/3 are in 2 1/3​
ycow [4]

Answer:

3.5

Step-by-step explanation:

2 1/3 is equal to 7/3 and 2 goes into 7, 3.5 times.

7 0
3 years ago
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Identify a1 r and n for the sum of the geometric sequence. 1/2 + 3/8 + 9/32 + 27/128 + 81/512
Bess [88]

Answer:

a1=1/2


r=3/4


n=5

Step-by-step explanation:

a1 is the first term in the geometric series


a1=1/2  


r is the common ratio of the first and second term


r=(3/8)/(1/2)


r=3/4



where n is the no of the term in the geometric series

In algebra, the polynomial remainder theorem or little Bézout's theorem is an application of Euclidean division of polynomials. It expresses that the rest of the division of a polynomial by a direct polynomial is equivalent to. Specifically, is a divisor of if and just if a property known as the factor hypothesis.

The number multiplied at each stage of a geometric sequence is called its common ratio.



4 0
3 years ago
Read 2 more answers
(25 points) A construction crew is lengthening a road. Let y represent the total length of the road (in miles). Let x represent
Tresset [83]

Answer:

L=193

Step-by-step explanation:

Initial length of the road =57mi

L= Total length

D=number of days worked

Number of miles added in 1 day= 4mi

Therefore,

L=57+D*4

After 34 days,

L=57+(34*4)

L=193mi

8 0
3 years ago
A circle with its dimensions, in meters (m), is shown. What is the area, 0/1 in the meters, of the circle? Use 3.14 for pie. Rou
Vikentia [17]

Answer:21

Step-by-step explanation:

8 0
3 years ago
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Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa
Nataly_w [17]

Answer:

The first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

coefficient of x^{2} in the expansion of (2+x - x^{2})^{6} = (240 - 192) = 48

Step-by-step explanation:

(2+x)^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})

= 6_{C_{0}} \times x^{0} \times 2^{6}  + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4} + terms involving higher powers of x

= 64 + 192 \times x^{1} + 240 \times x^{2} + terms involving higher powers of x

so, the first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

Again,

(2+x - x^{2})^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})

Now, by inspection,

the term x^{2} comes from k =5 and k = 6

for k = 5, the coefficient of  x^{2}  is , (-32) \times 6 = -192

for k = 6 , the coefficient of x^{2} is, 6_{C_{2}} \times 2^{4} = 240

so,   coefficient of x^{2} in the final expression = (240 - 192) = 48

3 0
2 years ago
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