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chubhunter [2.5K]
4 years ago
10

What are the solutions to the inequality?

Mathematics
1 answer:
denis23 [38]4 years ago
8 0

(x - 3)(x + 5) \leqslant 0 \\ \begin{cases}x - 3 \geqslant 0 \\x + 5 \leqslant 0 \end{cases} \: \vee \: \begin{cases} x - 3 \leqslant 0\\x - 5 \geqslant 0 \end{cases} \\ \Leftrightarrow \begin{cases}x \geqslant 3 \\ x \leqslant  - 5\end{cases} \: \vee \:  \begin{cases}x \leqslant 3 \\x \geqslant   + 5 \end{cases} \\ \Leftrightarrow x\in\emptyset \: \vee \:  - 5 \leqslant x \leqslant 3 \\ \Leftrightarrow  - 5 \leqslant x \leqslant 3

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Answer:

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Step-by-step explanation:

We want to simplify;

\frac{4}{9}\div 2

We can rewrite to get;

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We multiply the first fraction by the multiplicative inverse of the second fraction to get;

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This gives us;

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Multiply;

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