First you have to write the equation. in the scenario, use standard form.
Ax+By=C
plug the numbers in. A=2.50, B=1.25, and C is the total, 356.25. the 180 doesn't come in quite yet.
your equation is 2.50x+1.25y=356.25. now, since they only bought 180 items, you can't go past that.
I am sorry, but I am about to leave for school, and therefore do not have enough time to answer the last of your question. I hope the part I could answer has helped you.
Answer:
its 152 i know cause i just did this....
Step-by-step explanation:
Answer:
The probability of landing on blue on spinner 1 is 3/8 theoretically. The probability of landing green on green on spinner 1 is 5/8 theoretically. The probability of landing on blue on spinner 2 is 2/6, which is 1/3. The probability of landing on either green or purple on spinner 2 is 3/6, or 1/2. The probability of landing on yellow on spinner 2 is 1/6. The probability of not landing on green on spinner 2 is 4/6, or 2/3. The experimental probability, you have to do, since only you can do that. So glad I can help, but can you please give me brainlist?
Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC; 
in triangle ΔFGH;
Segment 
= 14 Segment 
= 14
Segment 
= 27 Segment 
= 19
Segment 
= 19 Segment 
= 2·y + 5
∡A = 32° ∡G = 32°
∡A = ∠BAC which is the angle formed by segments = 14 and = 19
Therefore, segment = 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments = 14 and = 19
Therefore, segment = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
≅ by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴ = = 27° y definition of congruency
= 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27°
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°
Answer:
0
Step-by-step explanation:
3x - 9 if x = 3
Substitute:
3(3) - 9 =
9 - 9 = 0
This can be written as a function: f(x) = 3x - 9
f(3) = 3x - 9
f(3) = 3(3) - 9
f(3) = 9 - 9
f(3) = 0
-Chetan K
