Answer:
(g · f)(4) = 45
Step-by-step explanation:
f(x)=4x+1
g(x)=x² - 4x- 5
(g · f)(x) = 4(x² - 5) + 1
(g · f)(4) = 4(4² - 5) + 1
Following pemdas
(g · f)(4) = 4(16 - 5) + 1
(g · f)(4) = 4(11) + 1
(g · f)(4) = 44 + 1
(g · f)(4) = 45
Answer:
7d+11
Step-by-step explanation:
Pretty much just addition.
3d+4d+2+9
(3d+2)+(4d+9) = 7d+11.
297/11 = 27
So we have 27 groups of 11 students. If there are 2 chaperones for every 11 students, then we can do:
27x2=54
There are 54 chaperones on the field trip.
Answer:
The area of the rectangle on the left side is

The area of the bottom rectangle is

The total area of the composite figure will be

Step-by-step explanation:
The area of any given rectangle can be found by multiplying the length of that rectangle by its width. The rectangle on the left side has a length of 9cm but the width is unknown. To find the width, we subtract 6cm from the width of the bottom rectangle: 10cm. And that gives us 4cm.
Therefore, we can now calculate the area to be: length × width = 9cm × 4cm = 36cm²//
The area of the bottom rectangle can be found similarly by multiplying the length: 2cm by the width: 6cm of that rectangle. And the result gives us: 2cm × 6cm = 12cm²//
The total area of the composite figure is calculated by adding the results from the left and bottom rectangles together. And that gives us: 36cm² + 12cm² = 48cm²//
15.4m Square because That is what I got when I times those two together