Answer:
60 students passed, and 75 appeared in examination.
Step-by-step explanation:
Let's say s is the total number of students and p is the number of students who passed.
80% of the students passed, so:
0.8 s = p
If there were 10 less passers, and 15 less students (5 less failures), then the ratio of passers to failures would be 5/1.
(p − 10) / (s − p − 5) = 5 / 1
Simplify the second equation:
p − 10 = 5 (s − p − 5)
p − 10 = 5s − 5p − 25
6p = 5s − 15
Substitute the first equation.
6 (0.8 s) = 5s − 15
4.8 s = 5s − 15
0.2 s = 15
s = 75
p = 0.8 s
p = 60
60 students passed, and 75 appeared in examination.
The order does not matter, so we will be using combinations here. 52C1 is the first one since there is only one possibility. 16C1 is the second. You have to multiply these two, so 52 X 16 = 832.
Answer:
3.9 mi/h
Step-by-step explanation:
If the boy is rowing perpendicular to the current, the two vectors form a right triangle.
AB represents the downstream current, BC is the speed across the river, and AC is the ground speed of the boat
AC^2 = 2.4^2 + 3.1^2 =5.76 + 9.61 = 15.37
AC = sqrt(15.37) = 3.9 mi/h
The boat's speed over the ground is 3.9 mi/h.
The Area of the square is (side)^2
side is given to be 2^(4/9)
SO,
side^2 = [2^(4/9)]^2 = 2^(4/9 * 2) = 2^(8/9)
so the area of square is 2^(8/9) sq. inches.
Answer:
C
Step-by-step explanation:
∠ AFD = ∠ AFB + ∠ BFC + ∠ CFD
The 3 angles form a straight angle and sum to 180°, that is
4x + 5 + 6x + 3 + 5x + 7 = 180, that is
15x + 15 = 180 ( subtract 15 from both sides )
15x = 165 ( divide both sides by 15 )
x = 11
∠ CFD = 5x + 7 = 5(11) + 7 = 55 + 7 = 62°, thus
∠ AFE = ∠ CFD = 62° ( vertical angles are congruent )
