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kvv77 [185]
2 years ago
5

John drew a figure with two pairs of opposite sides that are parallel. Without more information, which two figures can we be sur

e he has drawn?
Mathematics
2 answers:
Oksi-84 [34.3K]2 years ago
4 0

Answer:

square

Step-by-step explanation:

jarptica [38.1K]2 years ago
3 0

Answer:

quadrilateral, square

Step-by-step explanation:

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(b) Eric removed 72 fish from his pond over a period of 9 days. He removed the same number of
Amanda [17]

Answer:

-8

Step-by-step explanation:

72 ÷ 9 = 8

The fish are being taken out, so negative.

I hope this helps!

pls ❤ and mark brainliest pls!

8 0
2 years ago
Estimate 40% of 128<br> Please help :c
Ivanshal [37]

Answer:

<u>51.2</u> is 40% of 128

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Which expressions are equivalent to g + h + (j + k)? Check all that apply.
Paha777 [63]

Answer:

3.

{ \tt{g + h + (j + k)}} \\  = (g + h) + j + k

5 0
3 years ago
Read 2 more answers
Consider the function f(x) = x3 + 7. What is the inverse of f(x)?
Brrunno [24]

Answer:

f(x)=x^3+7

y=x^3+7

x=y^3+7

y^3=x-7

y=cube root (x-7)

f(x) inverse=cube root of x-7

Step-by-step explanation:

7 0
3 years ago
A car insurance company has determined that 8% of all drivers were involved in a car accident last year. Among the 15 drivers li
svetlana [45]

Answer:

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

Step-by-step explanation:

For each driver surveyed, there are only two possible outcomes. Either they were involved in a car accident last year, or they were not. This means that we solve this problem using binomial probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem

15 drivers are randomly selected, so n = 15.

A success consists in finding a driver that was involved in an accident. A car insurance company has determined that 8% of all drivers were involved in a car accident last year.  This means that \pi = 0.08.

What is the probability of getting 3 or more who were involved in a car accident last year?

This is P(X \geq 3).

Either less than 3 were involved in a car accident, or 3 or more were. Each one has it's probabilities. The sum of these probabilities is decimal 1. So:

P(X < 3) + P(X \geq 3) = 1

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{15,0}.(0.08)^{0}.(0.92)^{15} = 0.2863

P(X = 1) = C_{15,1}.(0.08)^{1}.(0.92)^{14} = 0.3734

P(X = 2) = C_{15,2}.(0.08)^{2}.(0.92)^{13} = 0.2273

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2863 + 0.3734 + 0.2273 = 0.887

Finally

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.887 = 0.113

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

5 0
3 years ago
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