Answer:
1/6
Step-by-step explanation:
The probability of getting 2 the same colour here is 1 out of 6. Very low chance.
Answer:
Step-by-step explanation:
![t=\frac{k}{k-2} \\t(k-2)=k\\tk-2t=k\\-2t=k-tk\\-2t=k(1-t)\\\frac{-2t}{1-t}=k\\k= \frac{-2t}{1-t}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bk%7D%7Bk-2%7D%20%5C%5Ct%28k-2%29%3Dk%5C%5Ctk-2t%3Dk%5C%5C-2t%3Dk-tk%5C%5C-2t%3Dk%281-t%29%5C%5C%5Cfrac%7B-2t%7D%7B1-t%7D%3Dk%5C%5Ck%3D%20%5Cfrac%7B-2t%7D%7B1-t%7D)
Answer:
7 8/21, 7.6, 7 2/3, 7.71, 7 4/5
Step-by-step explanation:
none
The question is related to application of derivatives .
Let A represents the area and s represent the side length .
![A = s^2](https://tex.z-dn.net/?f=%20%20A%20%3D%20s%5E2%20)
![25=s^2](https://tex.z-dn.net/?f=%2025%3Ds%5E2%20%20)
![s =\sqrt{25} = 5](https://tex.z-dn.net/?f=%20%20s%20%3D%5Csqrt%7B25%7D%20%3D%205%20%20)
![A = s^2](https://tex.z-dn.net/?f=%20A%20%3D%20s%5E2%20%20)
Differentiating both sides with respect to t
It is given that ds/dt = 4cm/s
Substituting the values of s, ds/dt and on multiplying them, we will get
dA/dt = 2(5)(4) = 40 cm^2/s
Therefore rate of change of area when area=
and rate of change of side is 4 cm/s is 40 ![cm^2/s .](https://tex.z-dn.net/?f=%20cm%5E2%2Fs%20.%20)
The answer is 5.7 hope that helps