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pishuonlain [190]
3 years ago
11

Sidney is making greeting cards, which she will sell by the box at an arts fair. She paid $32 for a booth at the fair, and the m

aterials for each box of cards cost $3. She will sell the cards for $11 per box of cards. At some point, she will sell enough cards so that her sales cover her expenditures. How many cards will that take? How much will the sales and expenditures be?
Mathematics
1 answer:
borishaifa [10]3 years ago
4 0

So think of it like this she starts off $32 negative and subtract 3 from each box of cards she makes . So each box of cards she will make $8 that being said

32/8 =4 (it will take 4 box of cards to pay off her booth expense).

Sales would be 11x 4 =44

Expenditures would be 3x4 =32 (the amount used to make cards ) +32(the amount paid for the booth)

Which in total would be $64

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The fair spinner shown in the diagram above is spun.
julsineya [31]

Answer:

1/5

Explanation:

There are five choices in the spinner. <em>One </em>of the choices is labeled '5'. That means you will have one out of the 5 choices to get the choice labeled '5'.

Good day :)

8 0
2 years ago
An army base in the desert is located at the origin, O of an x-y coordinate system. A soldier at point P needs to determine his
Nutka1998 [239]

Answer/step-by-step explanation

The soldier at point P lie on a parabola because he determined his position and distances from towns A and B through measurement of the difference in timing (phase) of radio signals received from the two towns.

This analysis of the signal time difference gives the difference in distance of the soldier at P, from the towns.

This process is known as hyperbolic navigation.

These distances of point P from towns A and B is estimated by the soldier at point P, by measuring the delay localizes the receiver to a hyperbolic line on a chart.

Two hyperbolic lines will be drawn by taking timing measurements from the

towns A and B .

Point P will be at the intersection of the lines.

These distances of point P(The soldier's positions) from town A and town B were determined using the timing of the signals received from the two towns, due to the fact that point P was on a certain hyperbola.

8 0
3 years ago
Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0
vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3  = 0.

2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.

So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.

5 0
3 years ago
Claire is painting some doors that are all the same size. She used 2 liters of paint to cobe 1 3/5 doors. How many liters of pai
Deffense [45]

Answer:

1 \dfrac{1}{4} \ liters

Step-by-step explanation:

Given that:

Claire uses 2 liters of paint to cover 1 3/5 doors

Then in order for her to paint 1 door, She will need:

2 L = 1 3/5 door

x L = 1 door

x (L) = \dfrac{2 L \times 1 door }{ 1 \dfrac{3}{5}   \ door}

x (L) = \dfrac{2 L  }{ 1 \dfrac{3}{5}  }

x (L) = \dfrac{2 L  }{  \dfrac{8}{5}  }

x (L) = \dfrac{2 L\times 5  }{  8  }

x (L) = \dfrac{10 \ L }{  8  }

x(L) =1 \dfrac{1}{4} \  L

4 0
2 years ago
HOW CAN YOU WRITE 10/3 AS A DIVISION EXPRESSION AND AS A MIXED NUMBER?
Anni [7]

Answer: 10.3 would be a mixed number

Step-by-step explanation:

Divide 12 into 46. You get 3 with a remainder of 10. 3 is the whole number of the mixed number, 10 is the numerator of the fraction, and 12 is the denominator. The fraction can be reduced to 5/6.

5 0
3 years ago
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