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sashaice [31]
3 years ago
14

-6u-6y=66 2v+4y=-32 v=. Y=

Mathematics
1 answer:
Effectus [21]3 years ago
8 0
-6u-6y=66
2u+4y=-32
------------------
u = -6 and y = -5

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[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
3 years ago
What is the percent correct for a quiz score of 14 points out of 20.A.43%B. 53%C.70%D.75%
matrenka [14]
14 divided by 20 is 0.7
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6 0
3 years ago
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Vadim26 [7]

Answer:

m = - 1

Step-by-step explanation:

9m + 13 = 4

subtract 13 from both sides

9m = 4 - 13

9m = - 9

divide both sides by 9

m = - 1  (negative 1)

5 0
3 years ago
Help on questions 11 and 15 Add and simplify if possible
Svetllana [295]
\frac{16+x}{x^3}+\frac{7-4x}{x^3}=\frac{16+x+7-4x}{x^3}=\frac{23-3x}{x^3}\\\\======================================\\\\\frac{5}{t-1}+\frac{3}{t}=\frac{5t}{t(t-1)}+\frac{3(t-1)}{t(t-1)}=\frac{5t+3t-3}{t^2-t}=\frac{8t-3}{t^2-t}
7 0
3 years ago
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Find a​ point-slope form for the line with slope 1 over 5 and passing through the point ​-8, -7
Whitepunk [10]

Answer:

(1/5)x-5.4=y

Step-by-step explanation:

mx+b=y

m=(1/5)

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(1/5)(-8)+b=(-7)

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b=-5.4

(1/5)x-5.4=y

6 0
3 years ago
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