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Ber [7]
3 years ago
6

Using the order of operations, what should be done first to evaluate 12 divided by (negative 6) (3) + (negative 2)? Divide 12 by

5. Multiply –6 and 3. Divide 12 by –6. Add 3 and –2
Mathematics
2 answers:
koban [17]3 years ago
3 0

12 / (-6)(3) + (-2)

First divide 12 by -6

Ganezh [65]3 years ago
3 0

Answer:

divide 12 by -6

Step-by-step explanation:

exponents, parenthesis, divide, miltiplied

                                        subtract, add

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Find the area.<br> 5cm<br> 3cm<br> 4 cm
Ostrovityanka [42]

Answer:

6 cm²

Step-by-step explanation:

Since 3 side lengths are given, I assume that this figure is a triangle. The area of a triangle can be determined by using hero's formula.

\text{Area of triangle} = \sqrt{\text{s(s - a)(s - b)(s - c)}

⇒ s = Perimeter/2

⇒ a, b, and c = side lenths of triangle

<u>Replacing a, b, and c as the given side lengths:</u>

\implies \text{Area of triangle} = \sqrt{\text{s(s - 5)(s - 3)(s - 4)}

<u>Determining the perimeter of the triangle:</u>

\text{Perimeter of triangle = Sum of it's side lengths}

\implies \text{Perimeter of triangle =}\ 5 + 4 + 3

\implies \text{Perimeter of triangle =}\ 12 \ \text{cm}

<u>Determining the half of perimeter:</u>

\text{Half of perimeter} = s = \dfrac{\text{Perimeter}}{2}

\implies s = \dfrac{12}{2}

\implies s = 6

<u>Replacing the value of "s" in the formula:</u>

\implies \text{Area of triangle} = \sqrt{\text{6(6 - 5)(6 - 3)(6 - 4)}

<u>Evaluating the area:</u>

\implies \text{Area of triangle} = \sqrt{\text{6(6 - 5)(6 - 3)(6 - 4)}

\implies \text{Area of triangle} = \sqrt{\text{6(1)(3)(2)}

\implies \text{Area of triangle} = \sqrt{\text{6(6)}

\implies \text{Area of triangle} = 6 \ \text{cm}^{2}

6 0
2 years ago
Here's a graph of a linear function. Write the
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Answer:

y= 3/2x + 1

Step-by-step explanation:

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The answer is m=-1/2
4 0
4 years ago
Read 2 more answers
Can someone help me answer this please
Citrus2011 [14]

Answer:

N = 3/8

Step-by-step explanation:

let the number be N

let's express the word sentence as a mathematical expression:

"a number multiplied by 2/5"

= "N" multiplied by 2/5

= N x (2/5)

= (2N/5) ------- (1)

"a number multiplied by 2/5 is 3/20" can be written as:

(2N/5)    =  3/20  (multiplying both sides by 5)

2N = (3/20) x 5

2N = 3/4      (divide both sides by 2)

N = (3/4) ÷ 2

N = (3/4) x (1/2)

N = 3/8

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