Answer:
The perimeter (to the nearest integer) is 9.
Step-by-step explanation:
The upper half of this figure is a triangle with height 3 and base 6. If we divide this vertically we get two congruent triangles of height 3 and base 3. Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles: (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.
Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.
The lower half of the figure has the shape of a trapezoid. Its base is 4. Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle. Using the Pythagorean Theorem, we get
(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10. Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.
Then the perimeter consists of the sum 2√10 + 4 + 6√2.
which, when done on a calculator, comes to 9.48. We must round this off to the nearest whole number, obtaining the final result 9.
<h2>
Stella is correct about center and wrong about radius </h2>
Step-by-step explanation:
Equation of circle with (h,k) as center and radius r is given by,
(x-h)²+(y-k)² = r²
Here equation is
x²−8x+y²+2y=5
Changing in to (x-h)²+(y-k)² = r² form
x²−8x + 16 - 16 +y²+2y+1 - 1=5
(x-4)² - 16 + (y+1)² -1 = 5
(x-4)² + (y+1)² = 22
(x-4)² + (y+1)² = 4.69²
Center is (4,-1) and radius is 4.69
Stella is correct about center and wrong about radius
9x^2 + 4x^3
Hope this helped
Answer:
Step-by-step explanation:
The chosen topic is not meant for use with this type of problem. Try the examples below.
5
3
y
+
5
2
=
5
x
3
=
2
x
−
1
=
2
y
