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strojnjashka [21]
3 years ago
5

Graph the function 2 3^sqrt x+2 +4​

Mathematics
1 answer:
Ghella [55]3 years ago
8 0

Answer: b; y intercept between 8 and 4

Step-by-step explanation:

1. a; 2/3

2. b; 3, all real numbers except x=2

3. a; $.75

4. c; intercepting at (-3,-3)

5. b; 5

6. a; starts at 3

7. b; 1975

8. b; y intercept between 8 and 4

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Descompuneti in factori. x^2+4x-5=?
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<span>Assume that,
   x^2+4x-5 = 0 .......(1)
       Then, x^2+4x-5 = 0 x^2+5x-1x-5 =0
   x(x+5)-1(x+5) = 0
    (x+5) (x-1) = 0
       We get x=-5 and x=1
       Sub x=-5 in equ (1)
   (-5)^2+4(5)-5 = 0
     -25+20-5 = 0
    -25+25= 0
    0 = 0
       Sub x=1 in equ (1) (1)^2+4(1)-5 = 0
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3 years ago
There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,
lys-0071 [83]

<h2 /><h2>Here we go ~ </h2>

According to given information there are :

  • 5 red balls

  • 4 blue balls

  • 6 yellow balls

  • 10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

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\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{total \: red \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{25}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{1}{5}

<h3>2. what is the probability that the ball chosen is blue ?</h3>

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{total \: blue \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{25}

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{total \: yellow\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{25}

<h3>4. what is the probability that the ball chosen is green ?</h3>

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{total \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{25}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{2}{5}

<h3>5. what is the probability that the ball chosen is not green ?</h3>

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{total \: non \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{15}{25}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{3}{5}

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Will calculators or computers be needed to perform some calculations?
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