Answer:
-28m-12
Step-by-step explanation:hope that helps :)
=(−4)(3+7m)
=(−4)(3)+(−4)(7m)
=−12−28m
=−28m−12
PART 1.
Going westward:
Distance: 2400 miles
Rate (this is speed): (450-wind_speed) mph
Time: distance / speed = 2400 / (450-wind speed)
Going eastward:
Distance: 2400 miles
Rate (this is speed): (450+wind_speed) mph
Time: distance / speed = 2400 / (450+wind speed)
PART 2
Formula for speed:
speed = distance / time
Now we solve this for time:
time = distance / speed
11h = 2400 / (450+-wind_speed)
+- sign is put because in one case wind increases speed of plane and in other case it decreases speed.
PART 3
To solve for wind_speed we start by rearranging formula so that we have wind_speed on left side:
(450+-wind_speed) = 2400 / 11
(450+-wind_speed) = 218mph
To fly this distance in 11h speed of plane must be 218mph.
The only way to get this solution is if we substract wind speed:
450-wind_speed = 218
wind_speed = 450-218 = 232mph
Answer:
Given
f
(
x
)
=
4
⋅
7
x
For
x
=
−
1
we have
f
(
−
1
)
=
4
⋅
7
−
1
=
4
7
using
a
−
n
=
1
a
n
For x=2, we have
f
(
2
)
=
4
⋅
7
2
=
196
Step-by-step explanation:
Ok. Length = L, Base = B
P = 2L + 2B
We know that B = 3L or L = B/3
so that's P = 2/3B + 2B = 2/3B + 6/3B = 8/3B
Answer:
x = -3
Step-by-step explanation:
2/3x + 4 = 2
2/3x = 2 - 4
2/3x = -2
2x = -2 * 3
2x = -6
x = -6/2
x = -3
