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Salsk061 [2.6K]

3 years ago

14

You are given that sin(a)=8/17, with a in quadrant ii, and sin(b)=−5/13, with b in quadrant iii. find cos(a−b)

1 answer:

masha68 [24]3 years ago

5 0

1.5 is the answer too your question sir thanks.

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What is the discriminant of 9x2 + 2 = 10x?<br> –356 <br> –172 <br> 28<br> 72

Airida [17]

Answer:

<h2><em>C. 28</em></h2>

Step-by-step explanation:

7 0

3 years ago

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A teacher has a bag of candy. If she gives every student in her class 4 pieces of candy, she is left with 48 pieces of candy. Ho

yawa3891 [41]

Well you can't actually find a number, but you can make an equation.
lets call the bag of candy x, and the number of students in the teachers class S.

she gives every student in her class 4 pieces, so to find that amount, we have to multiply the number of students in her class by 4, the pieces of candy. 4S

afterwards she has 48 pieces, which is the endpoint, x is the starting point because that's the amount of candy the teacher started with.

so your equation is x-4S=48, but the thing is, the question is looking for the amount of students she gave candy to, so we have to isolate S, or in easier words; put S on one side, and the numbers on the other.

so the equation is S=1/4x-12

6 0

3 years ago

Which system of equations below will have infinite solutions?

ipn [44]

Answer:

All

Step-by-step explanation:

Because there are no equations for them so for all we know they all could have infinite solutions.

5 0

2 years ago

Please help me with this!

morpeh [17]

Answer:

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6 0

2 years ago

Noah and Lin are each trying to solve the equation x² - 6x + 10 = 0. They know that the solutions to x² = - 1 are i and -i, but

Leviafan [203]

Answer:

Solving the equation $x^2 - 6x + 10 = 0$ we get $x=3+i \ , \ x=3-i$

Step-by-step explanation:

Noah's step to solve the equation $x^2 - 6x + 10 = 0$ are:

$x^2 - 6x + 10 = 0\\x^2 - 6x = -10\\x^2 - 6x + 9 = -10 + 9\\(x-3)^2 = -1$

The next step is to take square root on both sides because: $\sqrt{x^2}=x$

$\sqrt{(x-3)^2}=\sqrt{-1} \\x-3=\pm\sqrt{-1} \\x=\pm(\sqrt{-1})+3 \\$

Now, we know that: $\sqrt{-1}=i$

$x=\pm(i)+3\\x=3+i \ , \ x=3-i$

So, Solving the equation $x^2 - 6x + 10 = 0$ we get $x=3+i \ , \ x=3-i$

8 0

3 years ago