Answer:
a) Right 0≤p<π/2 and 3π/2<p≤2π
left π/2 ≤ p ≤3π/2
stopped p=π/2 and p=3π/2
b) 5.5cm and its final position (2π, 0)
c) 6.5cm
Step-by-step explanation:
we must find where the function becomes negative, positive and zero
(according to the graph)
the particle moves to the right where the function is positive
0≤p<π/2 and 3π/2<p≤2π , the particle moves to the left where the function is negative π/2 ≤ p ≤3π/2, and stopped p=π/2 and p=3π/2
s(t)=∫v(t)dt also s(t) = 5sin(t)
(according to the graph 2)
The displacement of the particle is 5.5 and its final position
(2π, 0)
The total displacement of the particle is 6.5
Answer:
(10,0), (0,5), (1,2)
Step-by-step explanation:
The equations that can be used are 10T + 5S = 190 and T + S = 30.
<h3><u>Equations</u></h3>
Given that the girls tennis team was interested in raising funds for an upcoming trip, and the team sold tumblers for $10 and sun hats for $5, and when the sales were over, the team had earned $190 and sold 30 total products, which included a mix of tumblers and hats, to determine which equations can be used to represent the situation, the following calculations must be made:
- T + S =190
- -It cannot be used because it has any relationship with the price of the products.
- 10T + 5S = 30
- -It cannot be used because it only considers the quantity variable.
- T + S = 30
- -It can be used as it shows the amount of products sold.
- 10T + 5S = 190
- -It can be used because it relates the total price to the quantity of each product.
- T + S = 15
- -It cannot be used because it only considers the price variable.
- 5T + 10S = 190
- -It cannot be used because it erroneously relates the price of each product.
Therefore, the equations that can be used are 10T + 5S = 190 and T + S = 30.
Learn more about equations at brainly.com/question/26511270.
Answer:
The number of each kind of apartment in the building is 130 .
Step-by-step explanation:
Given as :
The total number of floor in a building = 15
The number of apartment on each floor = 26
So, The total number of apartment = 26 × 15 = 390
The number of kinds of apartment in the building is 3 , i.e 1-bedroom , 2-bedroom , 3-bedroom
Let The number of each kind of apartment in building = x
So, According to question
The number of each kind of building = 
or, x = 
∴ x = 130
Hence The number of each kind of apartment in the building is 130 . Answer
Answer:
To most closely estimate the difference, I would round 62,980 to the nearest thousand, so it will be 63,000. That is because when rounding, 63,000 is large enough so that adding will be easy, and 62,980 is relatively close to 63,000.
I would round 49,625 to the nearest thousand, since it would make the subtraction easier and 49,625 is only 375 units away from 50,000.
63,000 - 50,000 = about 13,000.
Hope this helps!
