We need to find the speed of a train. The formula for speed of an object is equal to the total distance covered divided by total time taken. It can be given by :

$v=\dfrac{d}{t}\\\\v=\dfrac{50\ m}{120\ s}\\\\v=0.416\ m/s$

So, the speed of a train is 0.416 m/s.

3 0

3 years ago

Which set of numbers represents the domain of the set of order pairs (2,10), (-3,-10), (4,-1),(-5,2)

shutvik [7]

-3.4.-5 must be the answer

6 0

3 years ago

2. A square-based tent has the cross-sectional

ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

$sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m$

In ΔBGD,

$sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m$

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

= 1 m + 1.732 m

= 2.732 m

(b)

DF = ?

In ΔAOB,

$tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\$

According to the figure, OB = GE = 1.733 m

In ΔBGD,

$tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m$

According to the figure, DE = DG + GE

DE = 1 m + 1.733 m

DE = 2.733 m

Length of the base, DF = 2 X DE

DF = 2 X 2.733 m

DF = 5.466 m

8 0

3 years ago