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Nikolay [14]
3 years ago
11

I need help plzzzzzzzzzz

Mathematics
2 answers:
ozzi3 years ago
8 0
Ma th wa y is the answer
Nataly [62]3 years ago
7 0
The equation of the line that passes through points (5,5) and (5,8) is -3x+0y=-15. If I did that correctly.
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ASAP—-what is the missing value
olga_2 [115]

Answer:

im sure its 139

Step-by-step explanation:

because you do 128 + 93 which is 221

next, you do 360 (triangle angles) then you do 360-221

which gives you 139!

hope it helped! =)

8 0
3 years ago
Help pls do allll 6 questions... with steps
BaLLatris [955]
You just want to simplify right?!

45. (a^2b^3)(ab)^-2
= (a^2b^3)(a^-2b^-2)
= b
46. (-3x^3y)^2(4xy^2)
= (-9x^6y^2)(4xy^2)
= -36x^7y^4
47. 3c^2d(2c^3d^5) / 15c^4d^2
= 6c^5d^6 / 15c^4d^2
= 2/5c1/4x^4
48. -10g^6h^9(g^2h^3) / 30g^3h^3
= -10g^8h^12 / 30g^3h^3
= -1/3g^5h^9
49. 5x^4y^2(2x^5y^6) / 20x^3y^5
= 10x^9y^8 / 20x^3y^5
= 1/2x^6 1/3y^3
50. -12n^7p^5(n^2p^4) / 36n^6p^7
= -12n^9p^9 / 36n^6p^7
= -1/3n^3p^2

(Sorry it’s messy it’d look better if my phone could actually put the numbers to the power)
5 0
2 years ago
Let g be the function given by g(x)=limh→0sin(x h)−sinxh. What is the instantaneous rate of change of g with respect to x at x=π
lorasvet [3.4K]

The <em>instantaneous</em> rate of change of <em>g</em> with respect to <em>x</em> at <em>x = π/3</em> is <em>1/2</em>.

<h3>How to determine the instantaneous rate of change of a given function</h3>

The <em>instantaneous</em> rate of change at a given value of x can be found by concept of derivative, which is described below:

g(x) =  \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}

Where h is the <em>difference</em> rate.

In this question we must find an expression for the <em>instantaneous</em> rate of change of g if f(x) = \sin x and evaluate the resulting expression for x = \frac{\pi}{3}. Then, we have the following procedure below:

g(x) =  \lim_{h \to 0} \frac{\sin (x+h)-\sin x}{h}

g(x) =  \lim_{h \to 0} \frac{\sin x\cdot \cos h +\sin h\cdot \cos x -\sin x}{h}

g(x) =  \lim_{h \to 0} \frac{\sin h}{h}\cdot  \lim_{h \to 0} \cos x

g(x) = \cos x

Now we evaluate g(x) for x = \frac{\pi}{3}:

g\left(\frac{\pi}{3} \right) = \cos \frac{\pi}{3} = \frac{1}{2}

The <em>instantaneous</em> rate of change of <em>g</em> with respect to <em>x</em> at <em>x = π/3</em> is <em>1/2</em>. \blacksquare

To learn more on rates of change, we kindly invite to check this verified question: brainly.com/question/11606037

4 0
1 year ago
Pls helpp im failing
nydimaria [60]

Answer:

-41.6

Step-by-step explanation:

6 0
2 years ago
Write a verbal expression for 23f
Darya [45]
Twenty three times a number f
7 0
3 years ago
Read 2 more answers
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