N is an odd integer
The Next Larger is N+2
N+2 + 2N = -27 + 4N
3N + 2 = 4N - 27
0 = 4N - 27 - 3N - 2
0 = N - 29
N = 29
They are 29 and 31.
31 + 2(29) = 4(29) - 27
31 + 58 = 89 = 116 - 27 yes it works
It is not factorable. Factors of 21 are. 21 and 1
7 and 3. None of those add up to 12
Answer:
16 boxes
Step-by-step explanation:
160+50x=1000
Solve for the x and you'll get 16.8. Now, because you can't have a fraction of a box, and you can't go over the limit, the answer is 16 boxes.
(How to solve for x:
Get x by itself by subtracting 160 to both sides.
50x=1000-160
50x=840
Divide both sides by 50.
x=16.8)
Given that the First term of the Arithmetic sequence = -3
⇒ a = -3
We know that nth term of a Arithmetic sequence is : Tn = a + (n - 1)d
where a is the first term and d is the common difference
Given that 10th term is 15
⇒ T₁₀ = -3 + (10 - 1)d
⇒ -3 + (10 - 1)d = 15
⇒ 9d = 18
⇒ d = 2
⇒ Common difference of given Arithmetic Sequence is 2
D 32 because 160 divided by 5 is 32. hope this helped