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xxTIMURxx [149]
3 years ago
15

Credit card A has an APR of 26.2% and an annual fee of $30, while credit card B has anAPR of 27.1% and no annual fee. ALl else b

eing equal,at about what balance will the cards offer the same deal over the course of a year?(Assume all interest is compounded monthly.)
A. $261.78
B. $2617.85
C.$26,178.46
D.$26.18
Mathematics
2 answers:
butalik [34]3 years ago
5 0
Taking the quiz now. 
The answer is $2617.85.
Ipatiy [6.2K]3 years ago
3 0

Let the required balance be x.

Thus, for Card A, which has an APR of 26.2% and an annual fee of $30, the amount after a year when compounded monthly will be:

Amount_A=30+(1+\frac{0.262}{12})^{12}x........(Equation 1)

Likewise, for Card B, which has an APR of 27.1% and no annual fee, the amount after a year when compounded monthly will be:

Amount_B=0+(1+\frac{0.271}{12})^{12}x=(1+\frac{0.271}{12})^{12}x....(Equation 2)

Therefore, all else being equal, the balance, x, at which the cards offer the same deal over the course of a year can be found by equating the equations 1 and 2 and solving for x.

Thus we have:

30+(1+\frac{0.262}{12})^{12}x=(1+\frac{0.271}{12})^{12}x

30+(1.0218)^{12}x=(1.0226)^{12}x

Simplification gives us:

(1.0226)^{12}x-(1.0218)^{12}x=30

0.0122x=30

\therefore x\approx2459.02 dollars

This is the closest to the second option. Thus, option B is the correct option.

<u>Important Note:</u> If we do not round off the intermediate steps and calculate it directly using a calculator then we will get the exact answer of option B which is: $2617.85.


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Find a fraction equivalent to 5/7 whose squared terms add up to 1184.
bogdanovich [222]

The system of equations of two unknowns is formulated and solved.

\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left\{\begin{matrix} \ \ \ \dfrac{x}{y} = \dfrac{5}{7} \\ x^2+y^2 = 1184 \end{matrix}\right. \ \Longrightarrow \ x=\dfrac{5}{7}y  } \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left (\dfrac{5}{7}y \right )^2+y^2=1184\ \Longrightarrow\ 25y^2+49y^2=58016 } \end{gathered}$}

                                                              \large\displaystyle\text{$\begin{gathered}\sf \bf{74y^{2}=58016} \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \  \ \ \ \ y^{2}=784 } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ y=\pm\sqrt{784}=\pm28  } \end{gathered}$}

                                                                  \large\displaystyle\text{$\begin{gathered}\sf \bf{ x=\dfrac{5}{7}(\pm 28)=\pm 20  } \end{gathered}$}

The fraction that satisfies the request is \bf{\dfrac{20}{28}} , since in \bf{\dfrac{-20}{-28}} the negative signs are canceled and the first fraction is obtained.

3 0
1 year ago
9. 2 1/8 + 1 5/12
MrMuchimi

Answer:

9) Exact Form:  85 /24     Decimal Form:  3.541 6    Mixed Number Form:  3  13 /24

10) Exact Form:  17 /18     Decimal Form:  0.9  4

11) Exact Form: 3 /5          Decimal Form:  0.6

Step-by-step explanation:

9) Convert the mixed numbers to improper fractions, then find the LCD and combine.

10) Simplify the expression.

11) To subtract fractions, find the LCD and then combine.

4 0
3 years ago
Ay bro anyone wanna help, thanks
chubhunter [2.5K]

We use the pythagorean theorem and information about the rectangular prism to find the length of the hypotenuses that the spider walks along. Adding them together (5.39+5+5.83+3.91) gives us 20.13cm, the answer.

8 0
2 years ago
Add mix numbers Madison made a fruit salad . She used 3 1 fourth cups of straw berries and 2 1 fourths cups of blueberries. How
Zinaida [17]

Answer:

1 1/4

Step-by-step explanation:

For the strawberries, we will have to multiply 3 by 1/4 to get the total amount of strawberries used.

1/4 * 3 = 3/4

For the blueberries, we will have to multiply 2 by 1/4 to get the total amount of blueberries used.

1/4 * 2 = 2/4

Simplify that to get 1/2

Now we need to add 3/4 and 1/2

3/4 + 1/2 = 5/4

Simplify that and we get our answer;

1 1/4

7 0
3 years ago
(1+v)(v-7) i need help to solve this question
kramer
(1 + v)(v - 7)

1*(v - 7) + v(v - 7)

1*v - 1*7 + v*v - v*7

v - 7 + v² - 7v

v² - 7v + v - 7

 v² - 6v - 7

I hope this helps.
4 0
3 years ago
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